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3 years ago

An equinox occurs when

Physics

2 answers:

schepotkina [342]3 years ago

6 0

A! Good luck on your test!

Margaret [11]3 years ago

4 0

Answer: The correct answer is Option a.

Explanation:

An equinox is defined as an event that occurs when Sun's rays fall on the equator at noon and at an angle of 90°.

The axis of rotation of Earth must be perpendicular to the Sun's rays for this event to occur.

If the axis is titled to some angle even, then equinox will not occur.

Hence, the correct answer is Option a.

You might be interested in

Newton

vodomira [7]

Given parameters:

Mass on earth = 50kg

Unknown:

Mass on planet Xenon = ?

Weight on planet Xenon = ?

Mass is the amount of matter contained in a particular substance.

Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.

Weight = mass x acceleration due to gravity

Planet Xenon has half the gravitational force of Earth.

This translated gives $\frac{9.8}{2}$ = 4.9m/s²

Now, mass is always the same every where if the amount of matter in a substance does not change.

In this problem, mass = 50kg on planet xenon.

Weight = mass x acceleration due to gravity = 50 x 4.9 = 245N

The weight on Xenon is 245N and the mass is 50kg

4 0

3 years ago

A cyclist is moving at a speed of 15 m/s. If the combined mass of the bike and person is 100 kg,

MaRussiya [10]

Answer:

Explanation:

Momentum is equal to mass times velocity in kg and m/s, respectively. Therefore,

p = 100(15) so

p = 1500 $\frac{kg*m}{s}$

5 0

2 years ago

How can you verify the archimedes principle?

Ipatiy [6.2K]

Answer:

It is found that W1 - W2 loss in weight of solid when immersed in water is equal to the weight of the water displaced by the body. This verifies Archimedes' principle.

6 0

2 years ago

An aircraft with a mass of 10,000 kg starts from rest at sea level and takes off, then flies to a cruising speed of 620 km/h and

Natasha_Volkova [10]

Answer:

The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

Explanation:

Given that,

Mass of aircraft = 10000 kg

Speed = 620 km/h = 172.22 m/s

Altitude = 10 km = 1000 m

We calculate the change in potential energy

$\Delta P.E=mg(h_{2}-h_{1})$

$\Delta P.E=10000\times9.8\times(10000-0)$

$\Delta P.E=10000\times9.8\times10000$

$\Delta P.E=980000000\ J$

$\Delta P.E=980\ MJ$

For g = 10 m/s²,

The change in potential energy will be 1000 MJ.

We calculate the change in kinetic energy

$\Delta K.E=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)$

$\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2-0^2)$

$\Delta K.E=\dfrac{1}{2}\times10000\times(172.22^2)$

$\Delta K.E=148298642\ J$

$\Delta K.E=148.3\ MJ$

For g = 10 m/s²,

The change in kinetic energy will be 150 MJ.

Hence, The change in potential energy and kinetic energy are 980 MJ and 148.3 MJ.

7 0

2 years ago

PLEASE HELP

Gennadij [26K]

Answer:

3.675 m

Explanation:

$a_{x} =0$ $v_{xo}=100$ $a_{y} =-g$ $v_{yo}=0$

X-direction | Y-direction

$R=x_{o}+ v_{xo} t$ | $y=y_{o}+v_{yo}t+\frac{1}{2}a_{y}t^2$

$75=100t$ | $y=0+0+\frac{1}{2} (9.8)(0.75)$

$\frac{75}{100} =t$ | $y=3.675 m$

$0.75s=t$

Hope it helps

3 0

3 years ago