Moles of
= 6.5 mol
mole ratio of <span>
: HCl = 1 : 2
</span>∴ since <span>
cntain 6.5 mol, then HCL contains (2 * 6.5) mol
Thus moles of HCl = 13.0 </span><span>mol
Volume of HCl needed = </span>
=
<span>
</span><span> = 8.67 </span>
<span>then volume of HCL needed = 8.67 L
</span>
Answer:
4.3x10⁻⁵ mol/L.
Explanation:
Hello there!
In this case, since the dissolution of silver phosphate is not completely achieved due to its low solubility in water, we can represent this as an equilibrium problem by which it separates into silver and phosphate ions:
Which are slightly soluble in water; it means that the equilibrium expression is:
Thus, since we know the solubility product and the concentration of these ions in a saturated solution is represented by the reaction extent , we can write:
Thus, solving for we obtain:
Thus, the molar concentration of silver ions is 4.3x10⁻⁵ mol/L.
Best regards!
Answer:
1 - producer, 2 - primary consumer, 3 - secondary consumer, 4 - tertiary consumer
Explanation:
Instrumental methods of analysis rely on machines.The visualization of single molecules, single biological cells, biological tissues and nanomaterials is very important and attractive approach in analytical science.
There are several different types of instrumental analysis. Some are suitable for detecting and identifying elements, while others are better suited to compounds. In general, instrumental methods of analysis are:
-Fast
-Accurate (they reliably identify elements and compounds)
-Sensitive (they can detect very small amounts of a substance in a small amount of sample)
Hello!
First, we need to determine the
concentration of KHP. This concentration is:
The
neutralization reaction is:
KHP + NaOH → NaKP + H₂O
At the equivalence point:
So, the concentration of NaOH is
0,75MHave a nice day!