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Luda [366]
3 years ago
9

Quando aquecemos água em nossas casas, ao nível do mar, utilizando um recipiente aberto, sua temperatura nunca ultrapassa os 100

°C. Isso ocorre porque:
a) ao atingir essa temperatura, a agua perde sua capacidade de absorver calor.
b) ao atingir essa temperatura, a agua passa a perder exatamente a mesma quantidade de calor que esta recebendo, mantendo assim a temperatura constante.
c) as mudanças de fase ocorrem à temperatura constante.
d) ao atingir essa temperatura, a agua começa a expelir o oxigenio e outros gases nela dissolvidos.
e) as mudanças de fases de agua sempre ocorrem em 100 graus Celsius
Physics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

i dont speak spanish

Explanation:

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Answer:

the fur is unexpected

Explanation:

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3 years ago
What is it called cavity left behind in the rock after an organism's hard part has dissolved.
Lapatulllka [165]

Mold

Explanation:

A mold is a cavity that is left behind in the rock after an organism hard part has been dissolved. These are important fossils that useful in relative dating.

  • Some hard parts of organism are preserved in form of molds in soft sediments.
  • The outline and important details of the hard part is preserved when the mold dissolves away.
  • Fossil molds are representative on the internal outline of the hard parts of organisms.
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learn more:

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5 0
3 years ago
Is this snow or water
fredd [130]
I think its snow. Yup.
4 0
3 years ago
Read 2 more answers
You place a 55.0 kg box on a track that makes an angle of 28.0 degrees with the horizontal. The coefficient of static friction b
Radda [10]

Answer:

\theta=34 \textdegree

Explanation:

From the question we are told that:

Mass m=55kg

Angle \theta =28.0

Coefficient of static friction \alpha =0.680

Generally, the equation for Newtons second Law is mathematically given by

For

\sum_y=0

N=mgcos \theta

for

\sum_x=0

F_{s}=mgsin\theta

Where

F_{s}=\alpha*N\\\\F_{s}=\alpha*m*gcos \theta

F_{s}=0.68*55*9.8*cos 28

F_{s}=323.62N

Therefore

\alpha mgcos \theta=mg sin \theta

\theta=tan^{-1}(0.68)

\theta=34 \textdegree

6 0
2 years ago
Robert has just bought a new model roket, and is trying to measure its flight characteristics. The rocket engine package claims
rewona [7]
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh So Energy given to rocket = mgh Energy expended by engine = F x D (D= height where engine stops) Energy 'lost' to drag is the difference between the two values. please if this helped mark it as the brainiest answer.
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3 years ago
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