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sammy [17]
3 years ago
5

Explain the theory Steven Reiss developed and tested.

Physics
2 answers:
irinina [24]3 years ago
7 0

Steven Reiss proposed the theory of 16 basic desires (under theory of motivation) which he thought of when he was admitted in hospital and visualized the nurses enjoying their work.  

He deduced 16 desires which are as follows –  

1. Being curious

2. Being hungry

3. Being accepted

4. Taking care of offsprings

5. Being faithful

6. Requiring social justice

7. Being independent

8. Need for establishes environment

9. Need of work out

10. Will of power

11. Romance

12. Desire to save

13. Desire to establish social contact

14. Desire to feel safe and secure

15. Desire to establish oneself in society

16. Desire to revenge

NNADVOKAT [17]3 years ago
6 0
<span>A theory of motivation by Steven Reiss, the 16 Basic Desires Theory talks about the sixteen fundamental needs, values and drives that motivate a person.</span>
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Answer:

Part a)

I_{end} = \frac{mL^2}{3}

Part b)

I_{edge} = \frac{2ma^2}{3}

Explanation:

As we know that by parallel axis theorem we will have

I_p = I_{cm} + Md^2

Part a)

here we know that for a stick the moment of inertia for an axis passing through its COM is given as

I = \frac{mL^2}{12}

now if we need to find the inertia from its end then we will have

I_{end} = I_{cm} + Md^2

I_{end} = \frac{mL^2}{12} + m(\frac{L}{2})^2

I_{end} = \frac{mL^2}{3}

Part b)

here we know that for a cube the moment of inertia for an axis passing through its COM is given as

I = \frac{ma^2}{6}

now if we need to find the inertia about an axis passing through its edge

I_{edge} = I_{cm} + Md^2

I_{edge} = \frac{ma^2}{6} + m(\frac{a}{\sqrt2})^2

I_{edge} = \frac{2ma^2}{3}

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4 years ago
An electron is moving at a speed of 2.50 ✕ 104 m/s in a circular path of radius of 3.0 cm inside a solenoid. The magnetic field
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For the following questions consider a piece of copper wire. a. What type of bond is formed between the copper atoms? b. Describ
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Answer:

a. metallic bond

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Its false I got It right .


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cylindrical container is to be constructed to be open at the top with a volume of 27π cubic meters using the least amount of mat
Llana [10]

Answer:

radius comes out to be 3 m

height of the cylinder comes out to be 3m

Explanation:

given

volume of cylinder = 27π m³

π r² h = 27π

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surface area of cylinder open at the top

S = 2πrh + π r²

S = 2\pi \dfrac{27}{r} + \pi r^2

\frac{\mathrm{d} s}{\mathrm{d} r}=\frac{\mathrm{d}}{\mathrm{d} r} (2\pi \dfrac{27}{r} + \pi r^2)

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\dfrac{54\pi }{r^2} = 2\pi r\\r=3m

hence radius comes out to be 3 m

for height put the value in the equation 1

so, height of the cylinder comes out to be 3m

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