All categories

3 years ago

A rocket achieves a lift-off velocity of 500.0 m/s from rest in 30.0 seconds. Calculate the average acceleration of the rocket.

Physics

1 answer:

Anettt [7]3 years ago

6 0

Answer:

The average acceleration is 16.6 m/s² ⇒ 1st answer

Explanation:

A rocket achieves a lift-off velocity of 500.0 m/s from rest in

30.0 seconds

The given is:

→ The initial velocity = 0

→ The final velocity = 500 meters per seconds

→ The time is 30 seconds

Acceleration is the rate of change of velocity of the rocket

→ $a=\frac{v-u}{t}$

where a is the acceleration, v is the final velocity, u is the initial velocity

and t is the time

→ u = 0 , v = 500 m/s , t = 30 s

Substitute these values in the rule

→ $a=\frac{500-0}{30}=\frac{500}{30}=16.6$ m/s²

<em>The average acceleration is 16.6 m/s²</em>

You might be interested in

One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side

anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

$L1^2=L2^2=L^2=2^2+(H/2)^2$ Replacing this value in the previous equation:

$\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34$ Solving for H:

$H=\sqrt{52}$

We can now, calculate the angle between L1 and the 2m segment:

$\alpha = atan(\frac{H/2}{2})=60.98°$

If we make a sum of forces in the midpoint of the rope we get:

$-2*T*cos(\alpha ) + F = 0$ where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

$T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N$

7 0

3 years ago

A charge of 12 c passes through an electroplating apparatus in 2. 0 min. what is the average current?

Studentka2010 [4]

A charge of 12 c passes through an electroplating apparatus in 2.0 min, then the average current is 0.1 ampere.

<h3>What is an electric charge?</h3>

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.

Electric current is defined as the charge per unit of time.

The mathematical relation between current and the electric charge

I =Q/T

where I is the current flowing

Q is the total electric charge

T is the time period for which the current is flowing

As given in the problem A charge of 12 c passes through an electroplating apparatus in 2.0 min

Let us first convert the time period of minutes into seconds

1 min = 60 seconds

2 min = 2*60 seconds

=120 seconds

By using the above relation between electric current and electric charge

and by substituting the respective values of the charge and the time period

I =Q/T

I = 12c/120 seconds

I = 0.1 Ampere

Thus, the average current flowing through the apparatus would be 0.1 Ampere.

Learn more about an electric charge from here

brainly.com/question/8163163

#SPJ4

5 0

1 year ago

If the gas mileage of a Honda Civic car is 38 miles per gallon how many liters of gasoline would the car use to move from the Es

Troyanec [42]

Answer:

Explanation:

M = d/g........................ Equation 1

making g the subject of the equation,

g = d/M............................. Equation 2

Where M = mileage per gallon, d = distance move from Essex campus to Catonsville campus, g = amount of gasoline used

<em>Given: M = 38 miles per gallon, d = 37.2 km</em>

<em>If 1 kilometer = 0.62 miles</em>

<em>Then, 37.2 km = 37.2×0.62 miles = 23.064 miles</em>

<em>Substituting these values into equation 2,</em>

<em>g = 1.648 gallon</em>

<em>g ≈1.65 gallon</em>

<em>If, 0.264 gallon = 1 liters.</em>

<em>Then, 1.65 gallon = 1.65×1/0.264 = 6.25 liters.</em>

<em>Thus the car will use 6.25 liters of gasoline to move from the Essex campus to the Catonsville campus.</em>

8 0

3 years ago

A 4-m long wire with a mass of 40 g is under tension. A transverse wave for which the frequency is 860 Hz, the wavelength is 0.5

inn [45]

Answer:

Maximum acceleration will be $195372m/sec^2$

Explanation:

It is given mass m =40 gram = 0.04 kg

Length of the wire l = 4 m

Frequency of transverse wave f = 860 Hz

Wavelength $\lambda =0.5m$

Amplitude of the propagating wave $A=6.7mm=0.0067m$

Angular frequency is equal to $\omega =2\pi f=2\times 3.14\times 860=5400rad/sec$

Maximum acceleration is equal to $a=\omega ^2A=5400^2\times 0.0067=195372m/sec^2$

So maximum acceleration will be $195372m/sec^2$

4 0

3 years ago

How much work is done by a student holding a book with a force of 5N and walking forward 10 m?

inysia [295]

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 5 × 10 = 50

We have the final answer as

Hope this helps you

7 0

2 years ago