Answer:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Explanation:
In this case, we see a disk rotating at constant rate, the travelled distance of a point on the outside rim (), in centimeters, is determined by using this expression:
(1)
Where:
- Angular speed, in radians per second.
- Radius of the disk, in centimeters.
- Time, in seconds.
If we know that , and , then the travelled distance of the point is:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Answer:
v=77.62 m/s
Explanation:
Given that
h= - 300 m
speed of the bird ,u= 5 m/s
Lets take Speed of the berry when it hit the ground = v m/s
we know that ,if object is moving upward
v² = u² - 2 g h
u=Initial speed
v=Final speed
h=Height
Now by putting the values
v² = u² - 2 g h
v² = 5² - 2 x 10 x (-300) ( take g = 10 m/s²)
v² =25 + 20 x 300
v² ==25 + 6000
v² =6025
v=77.62 m/s
Therefore the final speed of the berry will be 77.62 m/s.
8M.
Because it would acumúlate to it
Answer:
move at constant velocity.
Explanation:
Newton's first law (also known as law of inertia) states that:
"when the net force acting on an object is zero, the object will keep its state of rest or if it is moving, it will continue moving at constant velocity".
In the case of the probe, friction in deep space is negligible, therefore when the engine is shut down, there are no more forces acting on the probe: the net force therefore will be zero, so the probe will move at constant velocity.