The acceleration of the car is 1.067 m/
.
<u>Explanation:</u>
Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.
As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as 
So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

So the acceleration of the car is 1.067 m/
.
Acoustic encoding in the encoding of sounds, that is, in laymen's terms. But in a more grammatically superior way of speech it is the encoding of auditory impulses.
Answer:
Explanation:
STEP 1
<u>Given</u>
Radius of cylinder = r = 25cm, 2.5m
mass = 27kg
cylinder is mounted so as to rotate freely about a horizontal axis that is parallel to and 60cm to the central logitudinal axis of the cylinder
height = 0.6m
<u>part 1</u>
The cylinder is mounted so as to rotate freely about a horizontal axis tha is paralle to 60cm from the central longitudinal axis of then cylinder. The rotational inertia of the cylinder about the axis of rotation is given by
<em>I = Icm + mh²</em>
<em>∴ I = 1/2mr² + mh² = 1/2x27x (0.5)² + 20 x (0.6)²</em>
<em>I=13.09kg.m²</em>
where
<em>I</em>cm is the rotational inertia of the cylinder about its central axis
m is the mass of the cylinder
h is the distance between the axis of the rotation and the central axis of the cylinder
r is the radius of the cylinder
<em> </em><em> I=13.09kg.m²</em>
<em>part2</em>
<em>from the conservation of the total mechanical energy of the meter stick, the change in gravitational potential energyof the meter stick plus the change in kinetic energy must be zero</em>
<em>Δk + Δu = 0</em>
<em>1/2 </em>I(w²-w²) = Ui-Uf
1/2 x 13.09w² = mgh
∴w=√20 x 9.8 x 0.6/(1/2 x 13.09) =117.6/6.5
w=18.09rad/s
Answer:
The angle of refraction in water 32.12°.
Explanation:
Given that,
Thickness = 5.0 cm
Index of refraction for oil = 1.15
Index of refraction for water = 1.33
Angle = 45°
We need to calculate the angle of refraction
When the ray of light enters from air to oil
Using formula of refraction

Where,
= refractive index of air
= refractive index of oil
Put the value into the formula





When the ray of light enters from oil to water
Using formula of refraction

Where,
= refractive index of water




Hence, The angle of refraction in water 32.12°.