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Elenna [48]
3 years ago
13

The baking soda looked like it dissolved in the vinegar. Sarah and Connor watched as the balloon expanded and filled with a gas.

Was this a physical or chemical reaction and why? A) chemical - gas produced B) physical - water bottle got hot C) physical - baking soda dissolved D) chemical - baking soda disappeared
Physics
2 answers:
malfutka [58]3 years ago
6 0
I think the answer is A- Chemical gas produced 
Brut [27]3 years ago
3 0

Answer: A) chemical - gas produced

Explanation: Physical change is a process in which there is no change in chemical composition of the substance.

Chemical change is a process in which there is a change in chemical composition of the substance.

Chemical process is accompanied by following changes

1. Change in color

2. Absorption or release of energy

3. Production of gas

4. Formation of precipitates.

Thus a chemical reaction is happening on mixing baking soda (NaHCO_3) and vinegar (CH_3COOH), there is production of CO_2 which expanded the balloon.

NaHCO_3+CH_3COOH\rightarrow CH_3COONa +CO_2(g)+H_2O


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How does an inclined plane trade force for distance??
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4 years ago
2) What does the specific heat capacity of a material tell you about how easy it is to heat up
Fed [463]

Answer:

High specific heat -> takes more energy to raise/lower object's temperature

Low specific heat -> takes less energy to raise/lower object's temperature

Explanation:

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6 0
3 years ago
All valid equations in physics have consistent units. Are all equations that have consistent units valid?
sweet [91]

Answer:

c. No. An equation may have consistent units but still be numerically invaid.

Explanation:

For an equation to be corrected, it should have consistent units and also be numerically correct.

Most equation are of the form;

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From the above, without the dimensionless constant the equation would be numerically wrong.

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KE = 0.5(mv^2)

Without the dimensionless constant '0.5' the equation would be dimensionally correct but numerically wrong.

8 0
3 years ago
Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150
alexgriva [62]

Answer:

\phi=4.52 rad

Explanation:

From the question we are told that

Distance b/e antenna's d=9.00m

Frequency of antenna RadiationF_r=120 MHz \approx 120*10^6Hz

Distance from receiver d_r=150m

Intensity of Receiver i= 10

Distance difference of the receiver b/w antenna's (r^2-r^1)=1.8m

Generally the equation for Phase difference \phi is mathematically given by

 \phi=\frac{2\pi}{\frac{c}{f_r}} *(r^2-r^1)

 \phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8

 \phi=\frac{4\pi}{5}  *1.8

<h3>  \phi=4.52 rad</h3>

Therefore phase difference f between the two radio waves produced by this path difference is given as

\phi=4.52 rad

7 0
3 years ago
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