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3 years ago

What does the symbol "E3" represent?

Chemistry

2 answers:

Ad libitum [116K]3 years ago

8 0

I think answer of this question is D

Anna71 [15]3 years ago

6 0

Answer:

your answer to your question is B

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A pharmacist wishes to strengthen a mixture from 10%alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of

Tomtit [17]

Answer:

2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

Explanation:

Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below

$n_{old}=7$ litres
$n_{new}=7+x$ litres

Also the quantity of alcohol is given as

$q_{old}=10 \% \, of \, 7 \, litres =0.7$

$q_{added}=x$

$q_{new}= 30 \% \,of \,new\, quantity = 0.3(7+x)$

Now the equation is as

$q_{old}+q_{added}=q_{new}\\0.7+x=0.3(7+x)\\0.7+x=2.1+0.3x\\x-0.3x=2.1-0.7\\0.7x=1.4\\x=2 \, litres$

So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

8 0

3 years ago

Metallic bonding occurs between atoms of

Pavel [41]

Answer:

Metallic bonding occurs when you have a metal in the solid or liquid state. The s and p valence electrons of metals are loosely held. They leave their “own” metal atoms. This forms a "sea" of electrons that surrounds the metal cations.

Explanation:

4 0

3 years ago

Help I need this lol!!!!!

brilliants [131]

Answer:

green

Explanation:

4 0

3 years ago

g Suppose a sample of an ideal gas in a container is subjected to a temperature change. A decrease in temperature will the kinet

Umnica [9.8K]

Answer:

323.15 °C

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Thus, at constant volume and number of moles, Pressure of the gas is directly proportional to the temperature of the gas.

P ∝ T

Also,

Using Charle's law

$\frac {P_1}{T_1}=\frac {P_2}{T_2}$

Given ,

P₂ = 2P₁

T₁ = 25 °C

T₂ = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

Using above equation as:

$\frac{P_1}{298.15}=\frac{2P_1}{T_2}$

$T_2=2\times 298.15\ K$

New temperature = 596.3 K

Also,

T(K) - 273.15 = T( °C)

<u>So, Temperature = 596.3 - 273.15 °C = 323.15 °C</u>

5 0

2 years ago

A helium balloon can hold about 6.8 mol of the gas. Assuming the balloon is kept at room temperature (25°C) and had a maximum of

Kipish [7]

Answer:

P= 138.6 atm or 1.4x10²

Explanation:

You will need to use PV=nRT to solve for P, pressure

Where the R constant is 0.08206 L atm mol^-1 K^-1

V is 1.2 L

T is temperature in kelvin, 273.15+25= 298.15

n is 6.8 mol

P*1.2=6.8*0.08206*298.15 ---> P*1.2=166.3700852 ---> P=166.3700852/1.2

P=138.6 atm

or 1.4x10²

6 0

2 years ago

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