Four of them pass a point every second.
Answer:
F = 2.49 x 10⁻⁹ N
Explanation:
The electrostatic force between two charged bodies is given by Colomb's Law:
![F = \frac{kq_1q_2}{r^2}\\](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7Br%5E2%7D%5C%5C)
where,
F = Electrostatic Force = ?
k = colomb's constant = 9 x 10⁹ N.m²/C²
q₁ = charge on proton = 1.6 x 10⁻¹⁹ C
q₂ = second charge = 1.4 C
r = distace between charges = 0.9 m
Therefore,
![F = \frac{(9\ x\ 10^9\ N.m^2/C^2)(1.6\ x\ 10^{-19}\ C)(1.4\ C)}{(0.9\ m)^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B%289%5C%20x%5C%2010%5E9%5C%20N.m%5E2%2FC%5E2%29%281.6%5C%20x%5C%2010%5E%7B-19%7D%5C%20C%29%281.4%5C%20C%29%7D%7B%280.9%5C%20m%29%5E2%7D)
<u>F = 2.49 x 10⁻⁹ N</u>