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tangare [24]
3 years ago
15

A boat traveled at a constant speed for 5 hours, covering a total distance of 132.3 kilometers. how fast was it going?

Physics
1 answer:
Llana [10]3 years ago
4 0
Velocity = distance (m) /time (s)

convert kilometers to metres (132300), substitute into formula.

convert hours to seconds (18000), substitute into formula. it becomes,

132300 divided by 18000 = 7.35 M/S 

always answer questions in the units given in the question.

to get m/s into km/h, multiply by 3.6, therefore it equals 24.46 km/h
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ddd [48]

A) 350 J

- The initial internal energy of the cup is

U_i = 230 J

- The final internal energy of the cup is

U_f = 580 J

According to the first law of thermodynamics:

U_f - U_i = Q+W

where

Q is the heat absorbed by the system

W is the work done on the system

The work done on the system in this case is 0, so we can rewrite the equation as

U_f - U_i = Q

And so we find the heat transferred

Q=580 J - 230 J=350 J

B) IN the cup

Explanation:

in this situation, we see that the internal energy of the cup increases. The internal energy of an object/substance is proportional to its temperature, so it is a measure of the average kinetic energy of the molecules of the object/substance. Therefore, in this case, the temperature (and the energy of the molecules of the substance) has increased: this means that heat has been transferred INTO the system from the environment (the heat came from the sun).

8 0
3 years ago
A rock falls off a cliff. How fast will it be going after falling for 4.33 seconds?
bixtya [17]

Answer:42.43m/s

Explanation:According to vf=vi+at, we  can calculate it since v0 equals to 0. vf=0+9.8m/s^2*4.33s= 42.434m/s

4 0
1 year ago
The lowest note on a grand piano has a frequency of 27.5 Hz. The entire string is 2.00 m long and has a mass of 400 g. The vibra
Norma-Jean [14]

Answer:

1456 N

Explanation:

Given that

Frequency of the piano, f = 27.5 Hz

Entire length of the string, l = 2 m

Mass of the piano, m = 400 g

Length of the vibrating section of the string, L = 1.9 m

Tension needed, T = ?

The formula for the tension is represented as

T = 4mL²f²/ l, where

T = tension

m = mass

L = length of vibrating part

F = frequency

l = length of the whole part

If we substitute and apply the values we have Fri. The question, we would have

T = (4 * 0.4 * 1.9² * 27.5²) / 2

T = 4368.1 / 2

T = 1456 N

Thus, we could conclude that the tension needed to tune the string properly is 1456 N

4 0
3 years ago
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