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tangare [24]
3 years ago
15

A boat traveled at a constant speed for 5 hours, covering a total distance of 132.3 kilometers. how fast was it going?

Physics
1 answer:
Llana [10]3 years ago
4 0
Velocity = distance (m) /time (s)

convert kilometers to metres (132300), substitute into formula.

convert hours to seconds (18000), substitute into formula. it becomes,

132300 divided by 18000 = 7.35 M/S 

always answer questions in the units given in the question.

to get m/s into km/h, multiply by 3.6, therefore it equals 24.46 km/h
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An isloated point charge produce an electric field with magnitude E at a point 2 m away. At a point 1 m from the charge magnitud
Nina [5.8K]

Answer:

the correct answer is C,      E’= 4E

Explanation:

In this exercise you are asked to calculate the electric field at a given point

         E = k \frac{q}{r^2}

indicates that the field is E for r = 2m

         E = \frac{ k q}{4}                  (1)

the field is requested for a distance r = 1 m

         E ’= k \frac{q}{r'^2}

         E ’= k q / 1

 

from equation 1

         4E = k q

       

we substitute

        E’= 4E

so the correct answer is C

8 0
3 years ago
Una cuerda de 20 pies se estira entre dos arboles. Un peso W cuelga del centro de la cuerda hace que el punto medio de la misma
Galina-37 [17]

Answer:

La magnitud de la masa del peso es 78.447 libras-masa.

Explanation:

La tensión es una fuerza de reacción de la cuerda causada por la acción de una fuerza externa. En este caso, esa fuerza externa es el peso que cuelga en el centro de la cuerda. Abajo hemos adjuntado una representación simplificada del enunciado.

Por las leyes de Newton, tenemos la siguiente ecuación de equilibrio conformada por tres fuerzas:

\vec T_{1} + \vec T_{2} + \vec W = (0, 0)\, [N] (1)

Donde:

\vec T_{1}, \vec T_{2} - Tensiones a cada lado de la cuerda, en newtons.

\vec W- Peso, en newtons.

Si sabemos que \vec T_{1} = T\cdot (\cos \alpha, \sin \alpha), \vec T_{2} = T\cdot (-\cos \alpha, \sin \alpha) y \vec W = W\cdot (0, -1), entonces tenemos la siguiente ecuación vectorial:

T\cdot (\cos \alpha, \sin \alpha) + T\cdot (-\cos\alpha, \sin \alpha) + W\cdot (0, -1) = (0,0)

T\cdot (0, 2\cdot \sin \alpha) = W\cdot (0, 1)

Esto permite reducir la anterior expresión a una fórmula escalar:

2\cdot T\cdot \sin \alpha = W

Donde \alpha es el ángulo de inclinación de la cuerda, medido en grados sexagesimales.

El ángulo de inclinación de la cuerda se determina mediante la siguiente fórmula trigonométrica inversa es:

\alpha = \tan^{-1} \left(\frac{2\,ft}{10\,ft}\right)

\alpha \approx 11.310^{\circ}

Si conocemos que \alpha \approx 11.310^{\circ} y T = 200\,lbf, entonces la magnitud del peso es:

W = 2\cdot (200\,lb)\cdot \sin 11.310^{\circ}

W \approx 78.447\,lbf

En el Sistema Imperial, las fuerzas son medidas en forma gravitacional, entonces la magnitud de la fuerza gravitacional del peso equivale a la magnitud de su masa. En síntesis, la magnitud de la masa es 78.447\,lbm.

La magnitud de la masa del peso es 78.447 libras-masa.

7 0
3 years ago
Toy car goes 2 meters in 3.1 seconds, find the average speed?
photoshop1234 [79]
Speed =distance over time

5 0
3 years ago
Select the correct description of how inductances are combined in series and in parallel
Ksivusya [100]

Answer:

it will be C

Explanation:

it will be C...

6 0
3 years ago
Determine the mechanical energy of this object. A 2 kg pendelum has a speed of 1 m/s at a height of 1/2 meter
Readme [11.4K]

Mechanical Energy: 10.81 J given that g = 9.81 \; \text{m}\cdot\text{s}^{-2}.

<h3>Explanation</h3>

The mechanical energy of an object is the sum of its kinetic and potential energy.

Kinetic Energy of this object:

\text{KE} = \dfrac{1}{2} \; m \cdot v^{2} = \dfrac{1}{2} \times 2 \times 1 = 1 \; \text{J}

Gravitational Potential Energy of this object:

g = 9.81 \; \text{m}\cdot\text{s}^{-2}.

\text{PE} = m \cdot g \cdot h = 2 \times 9.81 \times \dfrac{1}{2} = 9.81 \; \text{J}.

8 0
3 years ago
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