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raketka [301]
3 years ago
13

How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?

Chemistry
1 answer:
scoray [572]3 years ago
4 0

Answer:

  • <u>2.92 g</u>

Explanation:

<u>1) Data:</u>

a) V = 500.0 ml = 0.500 liter

b) M = 0.100

c) mass = ?

<u>2) Formulae:</u>

a) Molarity: M = n / V

b) Number of moles: n = mass in grams / molar mass

<u>3) Solution</u>

a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol

b) molar mass NaCl = 58.443 g/mol

c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g

Answer: 2.92 g

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