How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?
1 answer:
Answer:
Explanation:
<u>1) Data:</u>
a) V = 500.0 ml = 0.500 liter
b) M = 0.100
c) mass = ?
<u>2) Formulae:</u>
a) Molarity: M = n / V
b) Number of moles: n = mass in grams / molar mass
<u>3) Solution</u>
a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol
b) molar mass NaCl = 58.443 g/mol
c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g
Answer: 2.92 g
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