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3 years ago

100 + 50 + BRAINLIST PLEASE HELP!!!

Physics

2 answers:

irina1246 [14]3 years ago

6 0

Answer:

Explanation:

1. What are the forces acting on the block when it is hanging freely from the spring scale? What is the net force on the block? What are the magnitudes of each of the forces acting on the block? Explain.

When a block is hanging freely, two forces are acting on it = tension force from the spring scale and gravity force on the block itself. The net force is zero as the block is not accelerating. The magnitudes of tension and gravity force are the same but in opposite directions.

2. What are the forces that act on the block when it is placed on the ramp and is held in place by the spring scale? What is the net force acting on the block? Explain. (Assume that the ramps are frictionless surfaces.)

There are three forces acting on the block when it is placed on the ramp and is held in place by the spring scale: as in 1, there are tension and gravity but there is a third force - reaction force from the ramp surface on the block that is perpendicular to the surface. Again the block is not moving so the net force is zero.

3. What is the magnitude of normal force acting on the block when it is resting on the flat surface? How does the normal force change as the angle of the ramp increases? Explain. (Assume that the ramps are frictionless surfaces.)

On flat surface, the normal force is equal to the gravity force of the block i.e. its weight. On a vertical surface, the normal force is equal to zero. For the angle of ramp, θ, the normal force = weight * cos θ.

SOVA2 [1]3 years ago

3 0

Answer:

Explanation:

1. block is hanging freely - freely means there is no net force

from the spring scale - spring force

block - weight

magnitude of weight = magnitude of spring force as there is no net force

2. same thing - held in place means there is no net force

from the spring scale - spring force

block - weight

ramp - normal reaction

3. when its resting, there is no net force

magnitude of normal reaction force = magnitude of block weight

normal force reaction force decreases as angle of ramp increases from zero

reaction = weight x sin (ramp angle)

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By doing the ratio (2)/(1), we find an expression for g in terms of g':

$\frac{g}{g'}=\frac{\frac{GM}{R^2}}{\frac{GM}{(R+h')^2}}=\frac{(R+h')^2}{R^2}=\frac{(6.38\cdot 10^6+8848)^2}{(6.38\cdot 10^6)^2}=1.003$

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b) 519.3 N

The weight of an object near the Earth's surface is given by

$W=mg$

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In this problem,

m = 50 kg is the mass of the object

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Susbtituting,

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