Answer:
is the minimum depth of snow for survivable stopping.
Explanation:
Given:
- terminal velocity of fall,

- mass of the paratrooper,

- force on the paratrooper by the ice to stop him,

<u>Firstly, we calculate the deceleration caused in the snow:</u>



Now, using equation of motion:
....................(1)
where:
v = final velocity of the body after stopping
u = initial velocity of the body just before hitting the snow
a = acceleration of the body in the snow
s = distance through in the snow
Putting respective values in eq. (1)


Well you didn’t give answer choices but this sounds like... he’s stereotyping? Stereotypes... ageism....
Answer:
<em>Good Luck!</em>
Explanation:
Force applied by first student (F1) = 80 N
Force applied by the second student (F2) = 40 N
Displacement (d) = 10 m
Work done by first student (W1) = F1d = 80*10 = 800 J
Work done by second student (W2) = F2d = 40*10 = 400 J
Hence, the work done by the pushing student is 800 J and that by pulling student is
<h2> <u><em>400 J</em></u></h2>