4 years ago

Which process do hydrogen atoms use to make the Sun's energy?

Physics

1 answer:

Maru [420]4 years ago

8 0

Nuclear fusion, converts hydrogen atoms into helium

You might be interested in

In February 1955, a paratrooper fell 1200 ft from an

-Dominant- [34]

Answer:

$s=1.1107\ m$ is the minimum depth of snow for survivable stopping.

Explanation:

Given:

terminal velocity of fall, $u=56\ m.s^{-1}$

mass of the paratrooper, $m=85\ kg$

force on the paratrooper by the ice to stop him, $F=1.2\times 10^5\ N$

<u>Firstly, we calculate the deceleration caused in the snow:</u>

$a=\frac{F}{m}$

$a=\frac{120000}{85}$

$a=1411.765\ m.s^{-2}$

Now, using equation of motion:

$v^2=u^2+2a.s$ ....................(1)

where:

v = final velocity of the body after stopping

u = initial velocity of the body just before hitting the snow

a = acceleration of the body in the snow

s = distance through in the snow

Putting respective values in eq. (1)

$0^2=56^2+2\times (-1411.765)\times s$

$s=1.1107\ m$

5 0

3 years ago

Light hits a clear plastic bottle and a granite rock. Which choice most accurately describes the effect of visible light on the

balu736 [363]

Answer:

#4 is the accurate answer.

8 0

4 years ago

Read 2 more answers

mr.easton is 80 , and he thinks that all young people with longer hair use drugs .this is an example of:

natulia [17]

Well you didn’t give answer choices but this sounds like... he’s stereotyping? Stereotypes... ageism....

3 0

3 years ago

How much force is needed to accelerate a bicycle and rider with a total mass of 80 kg at a rate of 2.0 m/s2?

snow_tiger [21]

If I am not mistaken I think it is C. 320 N

5 0

4 years ago

Read 2 more answers

Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same

alekssr [168]

Answer:

Explanation:

Force applied by first student (F1) = 80 N

Force applied by the second student (F2) = 40 N

Displacement (d) = 10 m

Work done by first student (W1) = F1d = 80*10 = 800 J

Work done by second student (W2) = F2d = 40*10 = 400 J

Hence, the work done by the pushing student is 800 J and that by pulling student is

5 0

3 years ago