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Murljashka [212]
2 years ago
10

Newton’s law of universal gravitation a. is equivalent to Kepler’s first law of planetary motion. b. can be used to derive Keple

r’s third law of planetary motion. c. can be used to disprove Kepler’s laws of planetary motion. d. does not apply to Kepler’s laws of planetary motion.
Physics
2 answers:
Finger [1]2 years ago
5 0
Kepler derived his three laws of planetary motion entirely from
observations of the planets and their motions in the sky.

Newton published his law of universal gravitation almost a hundred
years later.  Using some calculus and some analytic geometry, which
any serious sophomore in an engineering college should be able to do,
it can be shown that IF Newton's law of gravitation is correct, then it MUST
lead to Kepler's laws.  Gravity, as Newton described it, must make the planets
in their orbits behave exactly as they do.

This demonstration is a tremendous boost for the work of both Kepler
and Newton.
Nikolay [14]2 years ago
5 0
<h3><u>Answer;</u></h3>

b. can be used to derive Kepler’s third law of planetary motion.

Newton’s law of universal gravitation <u><em>can be used to derive Kepler’s third law of planetary motion</em></u>.

<h3><u>Explanation</u>;</h3>

<u><em>Kepler's</em></u> three laws of planetary motion states that;

  • <em><u>All planets move about the Sun in elliptical orbits, having the Sun as one of the foci. </u></em>
  • <em><u>A radius vector joining any planet to the Sun sweeps out equal areas in equal lengths of time.</u></em>
  • <em><u>The squares of the sidereal periods of the planets are directly proportional to the cubes of their mean distances from the Sun</u></em>

<em><u>Newton's law of universal gravitation</u></em><em><u> states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.</u></em>

<u><em>Newton’s law of universal gravitation can be used to derive Kepler’s third law of planetary motion.</em></u>

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EleoNora [17]

Answer:

The tank is losing 4.976*10^{-4}  m^3/s

v_g = 19.81 \ m/s

Explanation:

According to the Bernoulli’s equation:

P_1 + 1 \frac{1}{2} \rho v_1^2 + \rho gh_1 = P_2 +  \frac{1}{2}  \rho v_2^2 + \rho gh_2

We are being informed that both the tank and the hole is being exposed to air :

∴ P₁ = P₂

Also as the tank is voluminous ; we take the initial volume  v_1 ≅ 0 ;

then v_2 can be determined as:\sqrt{[2g (h_1- h_2)]

h₁ = 5 + 15 = 20 m;

h₂ = 15 m

v_2 = \sqrt{[2*9.81*(20 - 15)]

v_2 = \sqrt{[2*9.81*(5)]

v_2= 9.9 \ m/s  as it leaves the hole at the base.

radius r = d/2  = 4/2 = 2.0 mm

(a) From the law of continuity; its equation can be expressed as:

J = A_1v_2

J = πr²v_2    

J =\pi *(2*10^{-3})^{2}*9.9

J =1.244*10^{-4}  m^3/s

b)

How fast is the water from the hole moving just as it reaches the ground?

In order to determine that; we use the relation of the velocity from the equation of motion which says:

v² = u² + 2gh ₂

v² = 9.9² + 2×9.81×15

v² = 392.31

The velocity of how fast the water from the hole is moving just as it reaches the ground is : v_g = \sqrt{392.31}

v_g = 19.81 \ m/s

4 0
2 years ago
A father pushes his child on a swing. He pushes with a force of 20 N or a distance of 1 m, with the force always maintained para
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Answer:

20 Joules

Explanation:

Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.

Therefore, we have;

Work done = Force x distance

i.e   Wd = Fs

Given that: F = 20 N and s = 1 m, then;

Wd = 20 N x 1 m

     = 20 Nm

The work done by the father is 20 Joules(Nm).

7 0
3 years ago
A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren
ludmilkaskok [199]

Answer : Height, h = 20.4 m

Explanation :

It is given that,

Mass of an object, m = 500 g = 0.5 kg

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The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :

PE = m g h

where,

h is the height of the cliff.

100\ J=0.5\ kg\times 9.8\ m/s^2\times h

h = 20.40 m

So, the height of the cliff is 20.4 m.

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3 years ago
Which planets are visible without a telescope
Annette [7]

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3 0
2 years ago
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Andrew [12]

Answer:

V₁ = 1.75 m³

Explanation:

Assuming the gas to be an ideal gas. At constant temperature, the relationship between the volume and temperature of an ideal gas is given by Boyle's Law as follows:

P_{1}V_{1} = P_{2}V_{2}

where,

P₁ = Initial Pressure of the Gas = 4 KPa

V₁ = Initial Volume of the Gas = ?

P₂ = Final Pressure of the Gas = 2 KPa

V₂ = Final Volume of the Gas = 3.5 m³

Therefore,

(4\ KPa)V_{1} = (2\ KPa)(3.5\ m^{3})\\\\V_{1}=\frac{2\ KPa}{4\ KPa}(3.5\ m^{3})\\\\

<u>V₁ = 1.75 m³</u>

4 0
3 years ago
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