The velocity of the pull through the ticker time graph it is going 50 times a second and 0.121 m and 10 dots
1 answer:
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The final velocity after the collision is 8.2 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.
If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.
Mathematically:
where:
is the mass of the first mosquito
is the initial velocity of the mosquito
is the mass of the raindrop
is the initial velocity of the raindrop
is the final combined velocity of the raindrop+mosquito
Re-arranging the equation and substituting, we find:
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Answer:
Approximately .
Explanation:
Cathode is where reduction takes place and anode is where oxidation takes place. The potential of a electrochemical reaction () is equal to
.
There are two half-reactions in this question. and
. Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of
should be positive.
In this case, is positive only if
is the reaction takes place at the cathode. The net reaction would be
.
Its cell potential would be equal to .
The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:
,
where
is the number moles of electrons transferred for each mole of the reaction. In this case the value of
as in the half-reactions.
is Faraday's Constant (approximately
.)
.