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4 years ago

The velocity of the pull through the ticker time graph it is going 50 times a second and 0.121 m and 10 dots

Physics

1 answer:

mariarad [96]4 years ago

7 0

Answer:

0,6

Explanation:

from the picture there are 10 dots. It means that the time needed to make these dot is

10/50 * 1 sec = 0.2 sec

the length (or we can say distance) of 10 dots are 12 cm. we must convert to meter so it become 0.12 m

v = d/t = 0.12/0.2 = 0.6 m/s

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The asthenosphere is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isost

lisov135 [29]

Complete option to the question:

A. The asthenosphere is broken up into large continental- and ocean-sized plates.

B. Convection currents within the asthenosphere push magma upward to create new crust.

C. Heat from deep within Earth is thought to keep the asthenosphere malleable.

D. The asthenosphere is the repository for parts of the lithosphere that are dragged downward in subduction zones.

Answer: The correct option is A (The asthenosphere is broken up into large continental- and ocean-sized plates.)

Explanation:

Among the components that makes up the earth crust are the lithosphere and the asthenosphere.

The LITHOSPHERE is the outer layer of the earth structure which consists of the upper part of the mantle and the crust.

The ASTHENOSPHERE is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments. It is denser and weaker layer of the upper mantle which permits the movement of tectonic plates in the lithosphere.

The asthenosphere is the repository for parts of the lithosphere that are dragged downward in subduction zones.Heat from deep within Earth is thought to keep the asthenosphere malleable. And the convection currents within the asthenosphere push magma upward to create new crust. But it is not broken up into large continental- and ocean-sized plates.

8 0

3 years ago

Is it true that if an object is moving it has kinetic energy

densk [106]

Yes an object in motion has kinetic energy

5 0

3 years ago

Read 2 more answers

Find the cube roots of 27(cos 327° + i sin 327° ). Write the answer in trigonometric form.

Sati [7]

Answer:

$z^{\frac{1}{3} }= -0.978 + i\cdot 2.836$ , $z^{\frac{1}{3} }= -1.967 - i\cdot 2.265$ , $z^{\frac{1}{3} }= 2.945 - i\cdot 0.571$

Explanation:

The cube root of the complex number can determined by the following De Moivre's Formula:

$z^{\frac{1}{n} } = r^{\frac{1}{n} }\cdot \left[\cos\left(\frac{x + 2\pi\cdot k}{n} \right) + i\cdot \sin\left(\frac{x+2\pi\cdot k}{n} \right)\right]$

Where angles are measured in radians and k represents an integer between $0$ and $n - 1$ .

The magnitude of the complex number is $27$ and the equivalent angular value is $1.817\pi$ . The set of cubic roots are, respectively:

k = 0

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{1.817\pi}{3} \right)+i\cdot \sin\left(\frac{1.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= -0.978 + i\cdot 2.836$

k = 1

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{3.817\pi}{3} \right)+i\cdot \sin\left(\frac{3.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= -1.967 - i\cdot 2.265$

k = 2

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{5.817\pi}{3} \right)+i\cdot \sin\left(\frac{5.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= 2.945 - i\cdot 0.571$

5 0

3 years ago

A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the su

tresset_1 [31]

Answer is D. The formula is Q=c*m*delta T. To raise m kg of substance with specific heat c by T kelvin, we need Q J of heat. Rearrange the equation, c=Q/(m*delta T). Plug in our numbers, Q=3.59kJ=3590J, m=0.200, T=20.0, c=3590/(0.200*20.0)=897 J(kg*K).

7 0

3 years ago

Water drips from the nozzle of a shower onto the floor 198 cm below. The drops fall at regular (equal) intervals of time, the fi

GenaCL600 [577]

Answer: 111.60 cm and 49.91 cm

Explanation:

In this, we have to make sure to keep in mind the Gravity effects on the drops. The drops will accelerate when they fall making them travel faster. This means, the velocity is not constant.

What is know:

Height (h) = 198 cm

Gravity (g) = 981 $cm/s^{2}$

Initial Velocity = 0

First, we can know how long it take to the drop to travel to the floor. It can be done with the following equation:

$x = Vo *t + \frac{1}{2} *a*t^{2}$

Where:

x is the distance which is 198cm

Vo is the Initial Velocity which is zero

t is the time the time it takes the drop to travel from the shower to the floor

a is the aceleration, which in this case is the gravity.

With the Initial Velocity equals zero the equations simply:

$198 cm = \frac{1}{2} *g*t^{2}$

Know we can search for the time:

$t =\sqrt{\frac{2 * 198 cm}{981 cm/s^{2} } }$

t = 0.635 s

This is the time it takes a drop to fall to the floor, with this time and knowing other 3 drops have driped from the shower by this time. We can calculate how much time it takes the shower to drip each drop.

Time for Drip = t/4

Time for Drip = 0.158

This time is the difference between each drop, using the same equation we can calculate where was each drop, because now it is know how much time had each drop after being drip from the shower.

Our first is already on the floor (198 cm) with 0.635 s, The second drops have been falling for (0.635s - 0.158) 0.477 s and our third drop for (0.635s - 0.158 - 0.158) 0.319 s

We can use the same equation from before to know how far have each drop traveled on these times.

$x = Vo *t + \frac{1}{2} *a*t^{2}$

We know the Initials Velocity are 0, know we need ot know the distance

$Distance for Second Drop = \frac{1}{2} * 981 cm/s^{2} * (0.477 s) ^{2}$

$Distance for Second Drop = 111.60 cm$

$Distance for Trird Drop = \frac{1}{2} * 981 cm/s^{2} * (0.319 s) ^{2}$

$Distance for Trird Drop = 49.91 cm$

8 0

3 years ago