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4 years ago

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1 answer:

Arte-miy333 [17]4 years ago

3 0

Answer: D

Explanation:

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Which instrument would be used to measure<br> the volume of a small jar of juice?

Sergio039 [100]

Answer:

Graduated cylinder

Explanation:

No explanation.

3 0

4 years ago

What is the atomic number for an element with 6 neutrons and a mass number of 10

Whitepunk [10]

$\bold{\huge{\blue{\underline{Answer}}}}$

$\bold{\underline{ Given :- }}$

Atomic number of an element with 6 neutrons and a mass number of 10

$\bold{\underline{ Let's \:Begin}}$

$\sf{We\: know\: that, }$

Atomic number is the number of protons in the nucleus of an atom

$\sf{Whereas ,}$

Mass number is the sum of protons and neutrons in the nucleus of an atom.

$\sf{We\: have \:number \:of \:neutrons = 6 }$

$\sf{ Mass\: number = 10 }$

$\bold{\underline{Therefore}}$

$\sf{ Mass\: number = Protons + neutrons}$

$\sf{ 10 = Protons + 6 }$

$\sf{ Protons = 10 - 6}$

$\sf{ Protons = 4 }$

$\sf{ Thus, \: the \: number \: of \: protons \: is \:4}$

$\bold{\underline{ Therefore,\:we\:know\:that, }}$

$\sf{ No\: of\: protons = Atomic \:number }$

$\sf{ 4 = Atomic \:number }$

$\sf { Hence, \:atomic\: number\: of\: the\: element\: is\: 4}$

5 0

2 years ago

Read 2 more answers

Plss help me asap!!!!

Tanzania [10]

Answer:

Based on the evidence, the layers, of which the fossils were discovered, the climate was a beach before becoming a forest.

Explanation:

8 0

2 years ago

Using the periodic table, determine the ion charges of the following elements if valence electrons were removed or added to reac

Dafna1 [17]

Hi, there!

The answer to your question is as follows:
Given that the valence electrons were removed or added to the following elements to fulfill the octet, barium's charge would be +2, iodine's -1, potassium's +1, and aluminum's +3.

I hope this helps!

5 0

3 years ago

Read 2 more answers

A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder

Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

$PV_1=nRT$

where,

P = pressure of gas = 1 atm

$V_1$ = volume of gas = ?

T = temperature of gas = $270^oC=273+270=543K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K$

$V_1=9.12L$

Now we have to calculate the volume at 24°C.

$PV_2=nRT$

where,

P = pressure of gas = 1 atm

$V_2$ = volume of gas = ?

T = temperature of gas = $24^oC=273+24=297K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K$

$V_2=4.99L$

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 9.12 L

$V_2$ = final volume = 4.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (4.99-9.12)L$

$w=4.13L.artm=4.13\times 101.3J=418.4J$

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0

3 years ago