A) 
The magnetic field strength around a current-carrying wire is given by the formula
where
is the vacuum permeability
I is the current in the wire
r is the radial distance from the wire
In this problem, we have
I = 200 A is the current in the wire
and we want to calculate the magnetic field strength at a distance of
r = 20 m
from the wire, so:
B) 4 %
The magnetic field strength at the surface of the Earth is
While the strength of the magnetic field generated by the wire at ground level is
Therefore, in percentage, it is:
Answer:
Explanation:
Scientific evidence takes note of the pattern of evolution. The evidence exists in a variety of categories, including direct observation of evolutionary change, the fossil record, homology, and biogeography.
Examples of the categories with their respective examples are:
Direct observation of evolutionary change: Development of drug resistant bacteria
Fossil record: Discovery of transitional forms of horses, Discovery of shells of extinct species
Homology: Similarities in mammalian forelimbs, Same genetic code in fireflies and tobacco plants, Vestigial pelvis in right whales
Biogeography: Similarity of endemic island species to nearby mainland species, The high concentration of marsupial species in Australia
Unless acted upon by an external force, an object in motion tends to stay in motion, and an object at rest prefers to stay at rest.
We can also see that we regress when a car abruptly begins to move from a condition of rest. The inertia of repose also contributes to this. Our bodies have a tendency to stay in a condition of rest, but as soon as the automobile starts moving, we start to regress.
Unless influenced by an imbalanced force, an item at rest stays at rest, and an object in motion keeps moving in a straight path at a constant pace. Second Law of Motion by Newton.
Learn more about motion here-
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Answer:
A) 17.7 m/s
B) 15.98 m
C) Zero
E) 9.8 m/s²
Explanation:
given information
distance, h = - 34 m
time, t = 5 s
A) What is the initial speed of the egg?
h - h₀ = v₀t - 
t², h₀ = 0
- 34 = v₀ 5 - \frac{1}{2} 9.8 5²
- 34 = 5 v₀ - 122.5
v₀ = 122.5 - 34/5
= 17.7 m/s
B) How high does it rise above its starting point?
v² = v₀² - 2gh
v = 0 (highest point)
2gh = v₀²
h = v₀²/2g
= 17.7²/2 (9.8)
= 15.98 m
C) What is the magnitude of its velocity at the highest point?
v = 0 (at highest point)
E) What are the magnitude and direction of its acceleration at the highest point?
g= 9.8 m/s², since the egg is moved vertically, the acceleration is the same as the gravitational acceleration.
