**Answer:**

**14.38 m/s**

**Explanation:**

We are given that

The coefficient of static friction between the road and the tires on a car=

Radius of curve=r=36 m

We have to find the speed will put the car on the verge of sliding as it rounds a level curve.

Magnitude of acceleration of car=

By Newton's second law

Where **=**Friction force

If car does not slip then

The maximum speed with which the car can round the curve without slipping

Substitute the values and taking g=

Hence, the speed of the car on the verge of sliding as it round a level curve=**14.38 m/s**

9.1 miles per hour because 2.2 is your hours right?

The horizontal speed has no effect on the answer.

It doesn't matter whether you flick a marble horizontally from the roof,

fire a high-power rifle horizontally from the roof, drive a school bus straight

off the roof, or drop a bowling ball from the roof with zero horizontal speed.

Their vertical speed is completely determined by gravity, (and it happens to

be the same for all of them).

Handy dandy formula for the distance covered by anything that starts out

with zero speed and accelerates to the end:

Distance = (1/2) (acceleration) x (time)²

If the beginning of the journey is on Earth, then the acceleration is

9.8 m/s² ... the acceleration of gravity on Earth. We'll assume that

the 55-meter rooftop in the question is part of a building on Earth.

55 meters = (1/2) (9.8 m/s²) x (time)²

Divide each side

by 4.9 m/s² : 55 m / 4.9 m/s² = (time)²

(time)² = (55/4.9) sec²

Square-root

each side: time = √(55/4.9 sec²)

= **3.35 sec **.

**Answer: Exothermic Reactions**

**In an exothermic reaction, energy is released because the total energy of the products is less than the total energy of the reactants. For this reason, the change in enthalpy, [latex]\Delta H[/latex], for an exothermic reaction will always be negative.**

**Explanation: please send a brainleast**