Answer:
AT
Explanation:
Dimensions of current = A
Dimensions of time = T
Current = Charge / time
Therefore Charge = Current × time
[Charge] = [Current] × [time]
= AT
Answer:
This question is incomplete
Explanation:
The question is incomplete because of the absence of options.
However, <u>the force that makes a paint cling to a wall is adhesive force</u>. Adhesive force is the force between two unlike substances like a liquid clinging to a solid surface.
The force between adhesives or glue is also the force that makes them sticky. <u>This force is referred to as cohesive force</u>. This is a force found in between similar molecules (unlike adhesive force found between dissimilar molecules).
<u>The force that makes wax to stick to a car is electromagnetic force</u>. This is a force between charged particles; whether they appear to be moving or not. These particles of opposite charges come together to form a neutral force. In this case, charged atoms of the car and the wax come together (which causes what we see as the wax sticking to the car).
As the speed of airplane is change due to jet stream
So the net speed is given as

now we can rearrange it as

now by the formula of vector difference we have

now plug in all values
![v_{plane} = \sqrt{365^2 + 136.73^2 - 2* 365* 136.73*cos22}[tex]v_{plane} = 243.7 km/hr](https://tex.z-dn.net/?f=v_%7Bplane%7D%20%3D%20%5Csqrt%7B365%5E2%20%2B%20136.73%5E2%20-%202%2A%20365%2A%20136.73%2Acos22%7D%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_%7Bplane%7D%20%3D%20243.7%20km%2Fhr)
so above is the speed of the plane
The question is incomplete, the complete question is;
A body initially at a all 100 degree centigarde cools to 60 degree centigarde in 5 minutes and to 40 degree centigarde in 10 minutes . What is the temperature of surrounding? What will be the temperature in 15 minutes?
Answer:
See explanation
Explanation:
From Newton's law of cooling;
θ1 - θ2/t = K(θ1 + θ2/2 - θo]
Where;
θ1 and θ2 are initial and final temperatures
θo is the temperature of the surroundings
K is the constant
t is the time taken
Hence;
100 - 60/5 = K(100 + 60/2 - θo)
100 - 40/10 = K(100 + 40/2 - θo)
8= (80 - θo)K -----(1)
6= (70 - θo)K -----(2)
Diving (1) by (2)
8/6 = (80 - θo)/(70 - θo)
8(70 - θo) = 6(80 - θo)
560 - 8θo = 480 - θo
560 - 480 = -θo + 8θo
80 = 7θo
θo = 11.4°
Again from Newton's law of cooling;
θ = θo + Ce^-kt
Where;
t= 0, θ = 60° and θo = 11.4°
60 = 11.4 + C e^-K(0)
60 - 11.4 = C
C= 48.6°
To obtain K
40 = 11.4 + 48.6e^-10k
40 -11.4 = 48.6e^-10k
28.6/48.6 = e^-10k
0.5585 = e^-10k
-10k = ln0.5585
k= ln0.5585/-10
K= 0.0583
Hence, the temperature in 15 minutes;
θ= 11.4 + 48.6e^(-0.0583 × 15)
θ= 31.7°
75km
I dont really know how to do the math but thats what my teacher told me when i asked