force between two parallel wire is
f/l = mueo*i1i2/2pir
f/l = 2*10^-7*i1i2/rl
i2 = f*r/2*10^-7*i1
i2 = 342.9 A
Refer to the diagram shown below.
The force, F, is applied at 5 cm from the elbow.
For dynamic equilibrium, the sum of moments about the elbow is zero.
Take moments about the elbow.
(5 cm)*(F N) - (30 cm)*(250 N) = 0
F = (30*250)/5 = 1500 N
Answer: 1500 N
Using the graph, which describes how Henry ran the 100m race;
a) It takes Henry 20seconds to run 100m
b) Henry's average speed over the race is; 5m/s.
According to the linear graph which describes the distance ran by Henry during the 100m race as a function of time.
a) Since the distance from start ran by Henry is plotted on the vertical axis, and the time is plotted on the horizontal axis;
To determine how long it took Henry to run 100m; The point corresponding to 100m is traced downward from the line of the graph and we find out that;
It takes Henry 20seconds to run 100m
b) Henry's average speed over the race is simply;
The slope of the distance-time graph.
Therefore,
- Average speed = (100-0)/(20-0)
Therefore, Henry's average speed over the race is; 5m/s.
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2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent