Answer:
Explanation:
given,
velocity factor = 4
Cross-sectional area of venules(A₁) = 10 cm²
cross sectional area of capillaries(A_2) = ?
continuity equation = Q = AV
now,
hence, the area of capillaries is equal to 2.5 cm₂
Answer:
W= - 1414.48 J : Work done by the friction force on the box.
Explanation:
Work concept
The work (W) of a given force is defined as the product of the force (F) by the distance(d) in which the force acted.
W= F*d :in (Joules) Formula (1)
Friction force concept
Ff=μk*N Formula (2)
μk=coefficient of kinetic friction
N= Normal force
We apply Newton's first law for forces in the direction of the axis y
∑Fy=0 Equation (1)
The forces acting on the box in the direction of the axis and are the following:
- Fy=Force of 210 N in y= 210*sen 39°= 132.16 N ( +y)
- W=Weight of box= m*g=30kg*9.8m/s² = 294N (-y)
- N =Normal force ( +y)
We apply equation (1) and do the algebraic sum of forces in y
Fy+N-W=0
132.16+N-294=0
N= 294-132.16=161.84 N
We apply formula (2) to calculate Ff:
Ff= -0.23*161.84=-37,22N The frictional force is negative because it goes in the opposite direction to the displacement.
We apply formula (1) to calculate the work done by the friction force on the box
W= - 37,22 N * 38 m = -1414.48 N*m = -1414.48 J
Answer:
Explanation:
HCE 20 ADIASM EPEGURNTE MSIMOLO
Answer:
Explanation:
The range of a projectile is given by the formula
where in this case, we have
d = 100 m is the range
u is the initial speed (the magnitude of the initial velocity)
g = 9.8 m/s^2 is the acceleration of gravity
is the angle of projection
Solving for u, we find:
Now we can easily find the components of the initial velocity:
So, the initial velocity of the ball is
where i and j are the unit vector indicating the horizontal and vertical direction.