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3 years ago

How do interpolation and extrapolation differ, which is more reliable

Chemistry

2 answers:

miv72 [106K]3 years ago

7 0

Answer:

These 2 are techniques whereby an individual tries to analyze and observe additional data points or information that may not be recorded and or obvious. From a graph, usually linear.

Interpolation involves the individual to be aware of the pattern observed or relationship between the 2 variables and tries to obtain a value that is in between 2 recorded or defined data points.

Extrapolation involves the individual to estimate and imagine what the graph would appear as if further data was collected, based on the previous recordings. This can be found out due to the relationship between the 2 variables in the graph.

Explanation:

MAXImum [283]3 years ago

6 0

These 2 are techniques whereby an individual tries to analyze and observe additional data points or information that may not be recorded and or obvious. From a graph, usually linear.

Interpolation involves the individual to be aware of the pattern observed or relationship between the 2 variables and tries to obtain a value that is in between 2 recorded or defined data points.

Extrapolation involves the individual to estimate and imagine what the graph would appear as if further data was collected, based on the previous recordings. This can be found out due to the relationship between the 2 variables in the graph.

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1) identify the physical state of the substances pictured.

Damm [24]

Can't help because APPARENTLY there is a picture that goes along with the questions. Post it and I can help.

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3 years ago

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NemiM [27]

Explanation:im not really sure about this one but i think it is either c or b

ANSWER:C im pretty sure.sorry if wrong

7 0

3 years ago

1) ΔS depends not merely on q but on ______ . Although there are many possible paths that could take a system from its initial t

Rus_ich [418]

Answer:

1) qrev/ reversible/ has only one particular value/ regardless of;

2) 1 mol of H₂(g) at 0ºC

3) a phase change/ remains constant/ increase

Explanation:

1) The change can occur in a reversible or an irreversible process. When the change is reversible, the system and the surroundings can be restored to their original state by exactly reversing the change. In an irreversible process, that is not possible.

The entropy variation (ΔS) is calculated only in the reversible process because, in the irreversible one, it's difficult to determine it. So, ΔS depends on qrev, which is the heat for the reversible process.

There is only one reversible isothermal path between two states, that's why it's easy to calculate ΔS for it.

The value of ΔS doesn't depend on the path, but only on the initial and the final states, so ΔS has only one particular value regardless of the path taken between states.

2) The entropy is the measure of the disorganization of a system, so when the molecules are more distant and vibrating, the entropy is higher (Sgas > Sliquid > Ssolid), and when the temperature increases, the entropy decreases (ΔS = qrev/T), so 1 mol of H₂(g) at 0ºC has the greatest entropy.

3) During a phase change, for a pure substance, the temperature remains constant, until all the substance changes for the other phase. The entropy is the measure of the disorganization of a system, so when the degrees of freedom and motion of the molecules increase, the system becomes more disorganized, so the entropy increases.

4 0

3 years ago

What is the molar concentration of a 2 liter solution containing 200 grams of glucose?

NARA [144]

The molar concentration is 1.11M.

<h3>What is molar concentration?</h3>

The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.

<h3>Given : </h3>

Volume of the solution = 2L

Mass of glucose given = 200g

Concentration of glucose= ?

<h3>Formula use: </h3>

Molarity = no. of moles of solute / volume of the solution (L)

Moles of solute = given mass of solute / molar mass of the solute

<h3>Solution: </h3>

No. of moles of solute( glucose ) = 200 / 180 = 1.11 moles'

Molarity = 1.11 / 2 = 0.5555 mol L ^(-1)

Therefore, the molar concentration of glucose in the solution = 0.555 mol L ^(-1)

To learn more about molar concentration :

brainly.com/question/15532279

#SPJ4

8 0

1 year ago

A propane stove burned 470 grams propane and produced 625 grams of water (this is the actual yield) C3H8 +5O2=3CO2+4H20. What wa

Liula [17]

Answer:

81.3%

Explanation:

Step 1:

The balanced equation for the reaction:

This is shown below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This includes:

Mass of propane (C3H8) = 470 g

Actual yield of water (H2O) = 625 g

Percentage yield of water (H2O) =?

Step 3:

Determination of the mass of propane (C3H8) burned and the mass of water (H2O) produce from the balanced equation. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 4 x 18 = 72g

From the balanced equation above,

44g of C3H8 was burned and 72g of H2O was produced.

Step 4:

Determination of the theoretical yield of H2O. This is illustrated below:

From the balanced equation above,

44g of C3H8 produced 72g of H2O.

Therefore, 470g of C3H8 will produce = (470x72)/44 = 769.09g of H2O.

Therefore, the theoretical yield of H2O is 769.09g

Step 5:

Determination of the percentage yield of water (H2O). This is illustrated below:

Actual yield of water (H2O) = 625g

theoretical yield of H2O = 769.09g

Percentage yield of water (H2O) =?

Percentage yield = Actual yield/Theoretical yield x100

Percentage yield = 625/769.09 x100

Percentage yield = 81.3%

Therefore, the percentage yield of water (H2O) is 81.3%

4 0

3 years ago