This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.
In this case, it is recommended to write the enthalpy for each substance as follows:

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and
and
are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Finally we convert this result to kJ:

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Answer:
The options are
A. a hypothesis
B. a theory
C. a research question
D. a scientific explanation
The answer is A. a hypothesis
Explanation:
A hypothesis is referred to as a brief explanation on the occurrence of an event.
In the example above using of warm water on plants was inferred to make it grow faster as hot water increases the metabolism.
Answer:
116.88g of table salt (NaCl) contains two formula units
Explanation:
Now,
We know that 1 formula unit of sodium chloride has a molar mass of 58.44g/mol
Hence;
Mass of 1 formula unit = 58.44g
Mass of x formula units = 116.88g
x = 116.88g * 1 formula unit/58.44g
x = 2 formula units
Therefore;
116.88g of table salt (NaCl) contains two formula units
A polar molecule is when the arrangement of the atoms in molecules are unequal where one end of the molecule has a positive charge while the other end has a negative charge. Examples of a polar molecule are water, ammonia, hydrogen sulfide and sulfur dioxide. The opposite is called a nonpolar molecule.