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GrogVix [38]
3 years ago
5

The following (unbalanced) reaction is one of the steps to producing acid rain [as H2SO4(aq)] from sulfur-containing coal. In a

study of this reaction, a flask contains an equilibrium concentration of the three substances SO2(g), O2(g) and SO3(g) held at a constant temperature.
SO2 (g) + O2 (g) <-----> SO3 (g)

The concentrations at equilibrium are found to be: [SO2] = 3.61 x 10-3M [O2] = 6.11 x 10-4 M [SO3] = 1.01 x 10-2 M

(a) Write the Equilibrium Constant expression, Kc for this specific reaction.
(b) Calculate the value of Kc for this temperature.
(c) Would you classify this as a product-favored reaction?
Chemistry
1 answer:
bulgar [2K]3 years ago
4 0

Answer:

a) kc= [SO3 ]/([SO2 ][O2 ])

b) kc= 2.27*10⁶ M⁻¹

v) the reaction is product-favored

Explanation:

for the reaction, the equilibrium constant is

SO2 (g) + O2 (g) <-----> SO3 (g)

he equilibrum constant is

kc= [SO3 ]/([SO2 ]*[O2 ])

replacing values

kc= [SO3 ]/([SO2 ]*[O2 ]) = 1.01*10⁻² M/(3.61*10⁻³M*6.11 x 10⁻⁴ M) = 2.27*10⁶ M⁻¹

since kc>>1 the reaction is product-favored

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The oxygen atom in a water molecule A is electrically neutral. B carries a negative electrical charge. C carries a positive elec
Klio2033 [76]

Answer: The oxygen atom in a water molecule carries a negative electrical charge.

Explanation:

A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

Hydrogen bonding (H-bonding) is an intermolecular force having partial ionic-covalent character. H-bonding takes place between a hydrogen atom (attached with an electronegative atom e.g. O, N and F) and an electronegative atom (O,N and F).

In , H_2O , O is a highly electronegative atom attached to a H atom through a covalent bond. Therefore O atom gets partial negative charge and H atoms get partial positive charge.  

7 0
3 years ago
Draw a line-bond structure for CBrN. Explicitly draw all H atoms. You do not have to include lone pairs in your answer. In cases
DochEvi [55]

Answer:

Br - C ≡ N

Explanation:

To draw the Lewis line-bond structure we need to bear in mind the octet rule, which states that in order to gain stability each <em>atom tends to share electrons until it has 8 electrons in its valence shell</em>.

  • C has 4 e⁻ in its valence shell so it will form 4 covalent bonds.
  • Br has 7 e⁻ in its valence shell so it will form 1 covalent bond.
  • N has 5 e⁻ in its valence shell so it will form 3 covalent bonds.

The most stable structure that respects these premises is:

Br - C ≡ N

It does not have any H atom.

8 0
2 years ago
Question 8 (9 points) <br><br>Match the lab equipment with its purpose
Deffense [45]

Answer:

\sf \boxed{4} \mapsto Pipet

\sf\boxed{7}\mapsto Test \:tube \: rack

\sf\boxed{3}\mapsto Test\: table

\sf\boxed{5}\mapsto Scoopula

\sf\boxed{1}\mapsto Graduated\: cylinder

\sf\boxed{9}\mapsto Bunsen \:burner

\sf\boxed{2}\mapsto Beaker

\sf \boxed{8}\mapsto Spot\: plate

\sf\boxed{6}\mapsto Goggles

Explanation:

Pipet is used to dispense a very small amount of liquid.

Test tube rack is used to hold multiple test tubes at the same time.

Test Table is used to view chemical reactions or hold or heat small amounts of substance.

Scoopula is used to dispense chemicals from a larger container.

Graduated cylinder is used to measure volume very precisely.

Bunsen burner is used to heat objects.

Beaker is used to transport heat or store substance.

Spot plate is used to observe the color changes of small quantities of a reacting mixture.

Goggles are used to protect the eyes from flying objects or chemical splashes.

_____________________________________________________

7 0
3 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
1.24 moles of magnesium arsenate are dissolved in 1.74 kg of solution. Calculate the molality of the solution.
aleksklad [387]

Answer:

Molality of the solution = 0.7294 M

Explanation:

Given:

Number of magnesium arsenate = 1.24 moles

Mass of solution = 1.74 kg

Find:

Molality of the solution

Computation:

Molality of the solution = Mole of solute / Mass of solution = 1.74 kg

Molality of the solution = 1.24 / 1.7

Molality of the solution = 0.7294 M

6 0
3 years ago
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