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trasher [3.6K]
4 years ago
13

A basesball is dropped from 100 meters above the surface of the earth. The baseball falls to the ground. What would happen if th

is baseball was dropped from 100 meters above the surface of the moon?
Physics
2 answers:
Readme [11.4K]4 years ago
6 0

Answer:

It would fall toward the Moon's surface

Explanation:

As you already know, a ball that is thrown 100 meters above the surface of the earth, would fall on the surface of the earth, due to the gravity of our planet, which attracts any object around it to its surface (and that is what we keep them attached to the planet's floor). The same would happen if a ball were launched 100 meters above the surface of the moon, but the ball would fall on the surface of the moon, for the same reason that is the gravity of the moon. As the Moon is much smaller than the Earth, its force of gravity is also less, therefore the bodies are attracted with less force to the lunar surface, even so the ball would fall on the surface of the moon because the distance between the ball and the earth is much greater than the distance between the moon and the ball.

Serjik [45]4 years ago
4 0

Given that, A basesball is dropped from 100 meters above the surface of the earth. If the same baseball was dropped from 100 meters above the surface of the moon, it will take more time to hit the ground as compare to the ball dropped on earth. This is moon's gravity is one-sixth of that of earth. Object falling on earth possess more force of attraction. So it will reach the earth in lesser time. At moon the force of attraction is low compare to that of earth. Object will take more time to reach the surface.

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Technician A says that the evacuation process will remove dirt and debris from the refrigerant system. Technician B says that th
GuDViN [60]

Answer: Technician B is right.

Explanation:

Evacuation process is used in refrigeration systems to remove moisture, air and non-profit condensable gases in order to achieve maximum function of the system.

vacuum pump is used to draw the sealed AC system into a vacuum. Evacuation of a refrigerant system also helps to maintain pressure, this is so as pulling a vacuum on the system is simply removing matter (mostly air and nitrogen) from inside the system so that the pressure inside drops below atmospheric pressure.

3 0
3 years ago
Potassium is a crucial element for the healthy operation of the human
Degger [83]

Answer:

1

  The mass of the Potassium-40 is  m_{40}} = 2.88*10^{-6} kg

2

  The Dose per year in Sieverts is   Dose_s = 26.4 *10^{-10}

Explanation:

From the question we are told that

   The isotopes of potassium in the body are Potassium-39, Potassium-40, and Potassium- 41

    Their abundance is 93.26%, 0.012% and 6.728%

   The mass of potassium contained in human body is  m = 3.0 g = \frac{3}{1000} = 0.0003 \ kg per kg of the body

    The mass of the first body is  m_1 = 80 \ kg

Now the mass of  potassium  in this body is mathematically evaluated as

       m_p =  m * m_1

substituting value

       m_p =  80  * 0.0003

      m_p  =0.024 kg

The amount of Potassium-40 present  is mathematically evaluated as

      m_{40}} =0.012% * 0.024

      m_{40}} = \frac{0.012}{100}  * 0.024

      m_{40}} = 2.88*10^{-6} kg

The dose of energy absorbed per year is mathematically represented as

          Dose  = \frac{E}{m_1}

Where E is the energy absorbed which is given as E = 1.10 MeV = 1.10 * 10^6 * 1.602*10^{-19}

    Substituting value

            Dose  = \frac{ 1.10 * 10^6 * 1.602*10^{-19}}{80}

            Dose  = 22*10^{-10} J/kg

The Dose in Sieverts is evaluated as

       Dose_s = REB * Dose

       Dose_s = 1.2 * 22*10^{-10}

       Dose_s = 26.4 *10^{-10}

             

3 0
3 years ago
Sort each item to the correct location,
Hitman42 [59]

Answer:

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3 0
3 years ago
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3 years ago
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A clock is designed that uses a mass on the end of a spring as a timing mechanism. If the oscillation time needed is exactly one
user100 [1]

Answer:

The value is  k  =  51.34 \  N/ m

Explanation:

From the question we are told that

   The  mass is  m =  1.3 \  kg

   The needed oscillation time is  T = 1 \ s  

 Generally the spring constant is mathematically represented  as

         k  =  \frac{4 \pi^2 * m }{ T^2}

=>      k  =  \frac{4* 3.142^2 * 1.3 }{ 1^2}

=>      k  =  51.34 \  N/ m

5 0
3 years ago
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