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trasher [3.6K]
4 years ago
13

A basesball is dropped from 100 meters above the surface of the earth. The baseball falls to the ground. What would happen if th

is baseball was dropped from 100 meters above the surface of the moon?
Physics
2 answers:
Readme [11.4K]4 years ago
6 0

Answer:

It would fall toward the Moon's surface

Explanation:

As you already know, a ball that is thrown 100 meters above the surface of the earth, would fall on the surface of the earth, due to the gravity of our planet, which attracts any object around it to its surface (and that is what we keep them attached to the planet's floor). The same would happen if a ball were launched 100 meters above the surface of the moon, but the ball would fall on the surface of the moon, for the same reason that is the gravity of the moon. As the Moon is much smaller than the Earth, its force of gravity is also less, therefore the bodies are attracted with less force to the lunar surface, even so the ball would fall on the surface of the moon because the distance between the ball and the earth is much greater than the distance between the moon and the ball.

Serjik [45]4 years ago
4 0

Given that, A basesball is dropped from 100 meters above the surface of the earth. If the same baseball was dropped from 100 meters above the surface of the moon, it will take more time to hit the ground as compare to the ball dropped on earth. This is moon's gravity is one-sixth of that of earth. Object falling on earth possess more force of attraction. So it will reach the earth in lesser time. At moon the force of attraction is low compare to that of earth. Object will take more time to reach the surface.

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Which type of tape is used to round sharp edges on splices using larger conductors?
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un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en l
Dmitriy789 [7]

Answer:

Acceleration = 5.77 m/s²

Distance cover in 13 seconds = 487.56 meter

Explanation:

Given:

Final velocity of mobile device = 75 m/s

initial velocity of mobile device = 0 m/s

Time taken = 13 seconds

Find:

Acceleration

Distance cover in 13 seconds

Computation:

v = u + at

75 = 0 + (a)(13)

13a = 75

a = 5.77

Acceleration = 5.77 m/s²

s = ut + (1/2)(a)(t²)

s = (0)(t) + (1/2)(5.77)(13²)

Distance cover in 13 seconds = 487.56 meter

8 0
3 years ago
Two bicyclist, originally separated by a distance of 20 miles, are each traveling at a uniform speed of 10 miles per hour toward
Radda [10]

Answer:

D = 25 miles

Explanation:

To solve this problem, we just need to know how much time it took both bicyclists to collide and that will be the same amount of time that the bee flew at 25miles per hour. With those values we could calculate the distance it traveled.

Since both bicyclists collide, we know that Xa=Xb, so:

Xa = V*t = 10*t     and    Xb = 20 - V*t = 20 - 10*t

10*t = 20 - 10*t      Solving for t:

t = 1 hour  Now we can calculate the distance for the bee:

D = Vbee * t = 25 * 1 = 25 miles

6 0
4 years ago
Which formation is one feature of karst topography?
steposvetlana [31]
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8 0
3 years ago
Read 2 more answers
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