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MArishka [77]
3 years ago
12

an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
6 0
.02047 = x / 0.02105 = 0.0004309mol
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Explanation:

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