Answer:
She turned back at the point at which she forgot she left her briefcase. If this isn't the correct answer, please be more specific in the question.
Explanation:
Answer:
THE MOLAR MASS OF THE GAS IS 147.78 G/MOLE
Explanation:
Using PV = nRT
n = Mass / molar mass
P = 732.6 mmHg = 1 atm = 760 mmHg
So therefore 732.6 mmHg will be equal to 732.6 / 760 = 0.964 atm
P = 0.964 atm
V = 275 mL = 275 *10 ^-3 L
R = 0.082 Latm/ mol K
T = -28 C = 273 - 28 K = 245 K
mass = 1.95 g
molar mass = unknown
Having known the other variables in the formula, the molar mass of the gas can be obtained.
PV = m R T/ molar mass
Molar mass = m RT / PV
Molar mass = 1.95 * 0.082 * 245 / 0.964 * 275 *10^-3
Molar mass = 39.1755 / 265.1 *10^-3
Molar mass = 39.1755 / 0.2651
Molar mass = 147.78 g/mol
The molar mass of the gas is 147.78 g/mol
The term is alkenes. one double carbon-carbon bond is referred to as Alkenes or Alkynes
Answer:
we find the chemical equilibrium constant by balancing the number of reactant and products
Explanation:
and after balancing using formula (KC) = Ratio of product / reactants
Answer:
The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
Explanation:
Step 1: Data given
For the reaction aA + bB ⇆ cC + dD
the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a
Step 2: The balanced equation
Fe2O3(s) + 3H2(g) --> 2Fe(s) + 3H2O(g)
Step 3: Calculate the equilibrium constant Kc
Kc = [C]^c * [D]^d/[B]^b*[A]^a
⇒with [C] = [Fe]
⇒ with c = 2
⇒with [D] = [H2O]
⇒with d = 3
⇒with [A] = [Fe2O3]
⇒with a = 1
⇒with [B] = [H2]
⇒with b = 3
Kc = [C]^c * [D]^d/[B]^b*[A]^a
Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
