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MArishka [77]
3 years ago
12

an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
6 0
.02047 = x / 0.02105 = 0.0004309mol
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What is the coefficient of MnO2when you balance the equation for this redox reaction? KCN( aq) + KMnO4( aq) + H2O( l) → KCNO( aq
chubhunter [2.5K]

Answer:

2MnO2 (s)

Explanation:

3KCN(aq) + 2KMnO4(aq) + 1H2O(l) → 3KCNO(aq) + 2MnO2(s) + 2KOH(aq)

Reactants:

K: 5

C: 3

N: 3

Mn: 2

O: 9

H: 2

Products:

K: 5

C: 3

N: 3

Mn: 2

O: 9

H: 2

8 0
3 years ago
PLEASE HELP! sketch the structure of the nitrogen-containing product that is formed when ethylamine reacts with water​
Aleksandr [31]

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In the picture you may see the chemical equation and the structure of the products.

5 0
4 years ago
PLEASE HELP
Nataliya [291]

Answer:

a

Explanation:

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3 0
3 years ago
Read 2 more answers
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
How could you separate I mixture of marbles, corks, and nails?
eduard
Use a magnet to get the nails use a contsiner of water to get the corks out
7 0
3 years ago
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