an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?
1 answer:
You might be interested in
Answer: 72 g of is formed.
Explanation:
To calculate the moles :
As is the excess reagent,
is the limiting reagent as it limits the formation of product.
According to stoichiometry :
1 mole of produce= 2 moles of
Thus 2 moles of will require=
of
Mass of
Thus 72 g of is formed.