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3 years ago

Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.

Chemistry

2 answers:

antiseptic1488 [7]3 years ago

7 0

Answer:

P(total) = 6.7 atm

Explanation:

Given data:

Partial pressure of N₂ = 3.5 atm

Partial pressure of O₂ = 2.8 atm

Partial pressure of Ar = 0.25 atm

Partial pressure of He = 0.15 atm

Total pressure = ?

Solution:

According to the Dalton law of partial pressure,

"The total pressure inside the gas cylinder having mixture of gases is equal to the sum of partial pressures of individual gas present in it"

Mathematical expression:

P(total) = P₁ + P₂ + P₃ + .........Pₙ

Now we will determine the total pressure of given gases.

P(total) = P₁ + P₂ + P₃ + P₄

P(total) =P(N₂) + P(O₂) + P(Ar) + P(He)

P(total) = 3.5 atm + 2.8 atm + 0.25 atm + 0.15 atm

P(total) = 6.7 atm

sp2606 [1]3 years ago

5 0

Answer:

6.7 atm

Explanation:

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At 35°C, K = 1.6 × 10^-5 for the reaction

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Answer:

a) [NOCl] = 0.968 M

[NO] = 0.032M

[Cl²] = 0.016M

b) [NOCl] = 1.992M

[NO] = 0.008 M

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Explanation:

Step 1: Data given

Temperature = 35°C = 308K

K = 1.6 × 10^-5

Step 2: The reaction

2 NOCl(g) ⇌ 2 NO(g) + Cl2(g)

For 2 moles NOCl we'll have 2 moles NO and 1 mol Cl2

Step 3

a. 2.0 mol pure NOCl in a 2.0 L flask

Concentration at the start:

Concentration = mol / volume

[NOCl] = mol / volume

[NOCl] = 2.0 / 2.0 L

[NOCl] = 1.0 M

[NO] = 0 M

[Cl] = 0M

Concentration at the equillibrium

[NOCl] = 1.0M - 2x

[NO] = 2x

[Cl2]= x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6*10^-5 = ((2x)² * x) / (1.0-2x)²

x = 0.016

[NOCl] = 1.0 - 2*0.016 = 0.968 M

[NO] = 2*0.016 = 0.032M

[Cl²] = 0.016M

b. 2.0 mol NOCl and 1.0 mol Cl2 in a 1.0 L flask

Concentration at the equillibrium

[NOCl] = 2.0 mol / 1.0 L = 2.0 M

[NO] = 0 M

[Cl2]= 1.0 mol / 1.0 L = 1.0 M

Concentration at the equillibrium

[NOCl] = 2.0M - 2x

[NO] = 2x

[Cl2]= 1.0 + x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6 *10^-5 = (2x)²*(1.0+x) / ((2.0-2x)²)

1.6 *10^-5= (2x)² * 1 )/2.0²

1.6 *10^-5= 4x² / 4 = x²

x = $\sqrt{1.6 *10^-5}$ = 4.0*10^-3

[NOCl] = 2.0 - 2*0.004 = 1.992M

[NO] = 2*0.004 = 0.008 M

[Cl2] = 1+ 0.004M = 1.004 M

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