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Monica [59]
3 years ago
12

Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.

Chemistry
2 answers:
antiseptic1488 [7]3 years ago
7 0

Answer:

P(total) =  6.7 atm

Explanation:

Given data:

Partial pressure of N₂ = 3.5 atm

Partial pressure of O₂ = 2.8 atm

Partial pressure of Ar = 0.25 atm

Partial pressure of He = 0.15 atm

Total pressure = ?

Solution:

According to the Dalton law of partial pressure,

"The total pressure inside the gas cylinder having mixture of gases is equal to the sum of partial pressures of individual gas present in it"

Mathematical expression:

P(total) = P₁ + P₂ + P₃ + .........Pₙ

Now we will determine the total pressure of given gases.

P(total) = P₁ + P₂ + P₃ + P₄

P(total) =P(N₂) + P(O₂) + P(Ar) + P(He)

P(total) = 3.5 atm + 2.8 atm + 0.25 atm + 0.15 atm

P(total) =  6.7 atm

sp2606 [1]3 years ago
5 0

Answer:

6.7 atm

Explanation:

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What volume would a sample of gas occupy in LITERS at 0.985 atmospheres and a volume of 3.65 liters if the pressure were raised
musickatia [10]

Answer:

3.18 L

Explanation:

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  • Final pressure (P₂): 861.0 mmHg
  • Final volume (V₂): ?

Step 2: Convert P₁ to mmHg

We will use the conversion factor 1 atm = 760 mmHg.

0.985 atm × 760 mmHg/1 atm = 749 mmHg

Step 3: Calculate the final volume of the gas

Assuming ideal behavior and constant temperature, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

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7 0
2 years ago
Which of the following contains a nonpolar covalent bond? O2 CO NaCI HF
jasenka [17]

Answer: The nonpolar covalent bond happens in an O₂ molecule.

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5 0
3 years ago
The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche
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Answer:

d=4.75\times 10^{-9}\ \text{inches}

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21\times 10^{-8}\ cm.

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}

So, the distance between the centers of the two oxygen atoms is 4.75\times 10^{-9}\ \text{inches}.

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2 years ago
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