Question

1. The uniform purely axial magnetic induction required by the experiment in a volume large enough to accommodate the Lorentz Tube is produced by the Helmholtz Coils. What is the magnetic induction due to a coil current 1.5 Ampere

Answer 1

Complete Question

The uniform purely axial magnetic induction required by the experiment in a volume large enough to accommodate the Lorentz Tube is produced by the Helmholtz Coils. What is the magnetic induction due to a coil current 1.5 Ampere? Convert the result in the still popular non-SI unit Gauss (1 Tesla = 10^4 Gauss).

B = N*mue*I/(2*r)

# of loops = 140

radius of the coil = 0.14m

Answer:

 The magnetic induction is $B = 2.639 \ Gauss$

Explanation:

From the question we are told that

     The coil current is  $I = 1.5 \ A$

     The number of loops is  $N = 140$

The magnetic field due to the current is mathematically represented as

           $B = \mu_o * N * I$

$\mu_o$ is the permeability of free space with value  $\mu_o = 4\pi * 10^{-7} N/A^2$

substituting value

           $B = 4\pi * 10^{-7} * 140 * 1.5$

           $B = 2.639*19^{-4} \ T$

From question

        (1 Tesla = $10^4 \ Gauss$).

=>      $B = 2.693 *10^{-4} *10^4 = 2.63 \ Gauss$

=>      $B = 2.639 \ Gauss$