Answer:
Explanation:
First, we find the mass of the air originally in the tank.
Density is given as mass divided by volume. It is given as:
Therefore, mass is:
Density of air = 
; Volume of the tank = 
The mass of the air initially in the tank is 7 kg.
After air is allowed to enter, the mass changes.
New density = 
The new mass will be:
We can now find the mass of air that has entered the tank:
Mass of air that entered tank = New mass of air - Original mass of air
M = 22.75 - 7.0 = 15.75 kg
The mass of air that entered the tank is 15.75 kg.
Answer:
(A)-Light-Bulb, Automobile Engine, Power Plant, Electric Motor
Explanation:
To get the least efficient to the most efficient the chart below explains how to the get it
Incandescent light bulb-5%
Florescent light bulb-20%
Electric motor-90%
Power plant-35%
Automobile engine-25%
Home oil furnace-80%
Complete Question
The complete question is shown on the first uploaded image
Answer:
a) The elongation of the composite bar is given as δ = 0.072 in
b) The axial stress induced in each material is = 5485.7 psi
Explanation:
The explanation to the answer above is shown on the second uploaded image
Answer:
5.833
Explanation:
Coefficient of Perfomance (COP) is the ratio of refrigeration effect to power input.
where RE is refrigeration effect and P is power input
Here, the power input is given as 30 kW
We also know that 1 ton cooling is equivalent to 3.5 kW hence for 50 tons, RE=50*3.5=175 kW
Now the 
Answer:
Enthalpy at outlet=284.44 KJ
Explanation:
We need to Find enthalpy of outlet.
Lets take the outlet mass m and outlet enthalpy h.
So from mass conservation
m=1+1.5+2 Kg/s
m=4.5 Kg/s
Now from energy conservation
By putting the values
So h=284.44 KJ
