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faltersainse [42]
3 years ago
11

a car whose mass is 1000kg is traveling at a constant speed of 10m/s. Neglecting any friction how much force will the engine hav

e to supply to keep going the same speed ?
Physics
2 answers:
AURORKA [14]3 years ago
7 0
This next statement is a big deal.  It should be up on a board, surrounded
by flashing red and yellow lights, and hung on the wall of every Science
classroom.   Although we never see it in our daily lives, it's fundamental to
the workings of the universe, and it's also Newton's first law of motion:

<em>Without friction, it doesn't take <u>ANY</u> force to keep a moving object
moving.  </em>
<em>Force is only required to <u>change</u> the object's speed, or to
<u>change</u> the direction </em>
<em>in which it's moving.</em>

The answer to the question is:  On a level road, and neglecting any friction,
the engine doesn't have to supply ANY force to keep the car going at the
same speed.
serg [7]3 years ago
5 0
Since you already know:

Force  =  mass *  acceleration.

acceleration =  (Velocity Change) / time.

Since we were told that velocity is constant, therefore Velocity Change = ZERO.

Therefore acceleration = ZERO.

Force = 1000 kg * ZERO = ZERO.

Force = 0 N.

Cheers.
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If you have 12 atoms of hydrogen before a chemical reaction how many atoms of hydrogen will be president after the chemical reac
kaheart [24]
If you have 12 atoms of hydrogen before a chemical reaction, the number of hydrogen atoms that will be present after the chemical reaction is 12 atoms.
The Law of Conservation of Mass (LOCOM) states that mass is neither created nor destroyed before and after any chemical reaction.
According to the Law of Conservation of Mass (LOCOM), a balanced chemical equation requires that the number of atoms on the reactant side must be equal to the number of atoms on the product side of any chemical reaction.
In this context, a chemical reaction having 12 atoms of hydrogen as reactants at the beginning, should also produce a total of 12 atoms of hydrogen as products at the end of the chemical reaction.
4 0
2 years ago
A physics student throws a softball straight up into the air. The ball was in the air for a total of 3.56 s before it was caught
meriva

Answer:

The initial velocity of the softball is 14.711 meters per second.

Explanation:

This is a case of an object which experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from air friction and Earth's rotation can be neglected.

From statement we must understand that the student threw the softball upwards and it is caught at original position 3.56 seconds later. Initial and final heights, time and gravitational acceleration are known and initial speed is unknown. The following equation of motion is used:

y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2} (Eq. 1)

Where:

y_{o} - Initial height of the softball, measured in meters.

y - Final height of the softball, measured in meters.

v_{o} - Initial velocity of the softball, measured in meters per second.

t - Time, measured in seconds.

g - Gravitational acceleration, measured in meters per square second.

If we know that y = y_{o}, t = 3.56\,s and g = -9.807\,\frac{m}{s^{2}}, the initial velocity of the softball is:

v_{o}\cdot (3\,s)+\frac{1}{2}\cdot (-9.807\,\frac{m}{s^{2}} )\cdot (3\,s)^{2} = 0

3\cdot v_{o} -44.132\,m= 0

v_{o} = 14.711\,\frac{m}{s}

The initial velocity of the softball is 14.711 meters per second.

8 0
3 years ago
How can you increase the gravitational potential energy (GPE) of an empty shoe box on the bottom shelf of a bookcase
Anettt [7]

Answer:

Add items to the box

Explanation: I did the test

5 0
3 years ago
Read 2 more answers
For a photoelectric tube, calculate the voltage which will be just sufficient to stop electrons emitted by the sodium photo-plat
Talja [164]

Answer:

1.11 V

Explanation:

Given that the Einstein photoelectric equation states that;

KE = E - Wo

E = energy of incident photon

Wo= work function of the metal

E = hf = 6.64 x 10-34 * 6 x 1014

E = 39.84 * 10^-20 J or 3.98  * 10^-19 J

KE = 3.98  * 10^-19 J - 2.2 x 10-19J

KE = 1.78 *  10^-19J

We convert this value of KE to electron volts

KE = 1.78 *  10^-19J/1.6 x 10-19C

KE = 1.11 eV

Hence; 1.11 V will be just sufficient to stop electrons emitted by the sodium photo-plate reaching the collector plate.

8 0
3 years ago
Смоктати півень мій друг
kaheart [24]
What uhhhhhhhhhhhhhhhhhhhhh

3 0
3 years ago
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