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3 years ago

1. A rock is dropped off a cliff and strikes the ground with an impact velocity of 35 m/s. How

Physics

1 answer:

MissTica3 years ago

4 0

Answer:

45 m

Explanation:

Use Big Five #5 with v0 = 0 (calling down the positive direction).

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Two stars in a faraway part of the Milky Way are orbiting each other as a binary star system. By

natita [175]

Answer: $M_{total}=$ 1.85

Explanation: Estimate the total mass of a binary system is done by a reformulation of Kepler's Third Law, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

$a^{3}=(M_{1}+M_{2})P^{2}$

where

a is semimajor axis in astronomical units (AU);

P is period measured in years;

$M_{1}+M_{2}$ is total mass of the two-stars system;

For the two stars faraway in the Milky Way:

1 year is equivalent of 365 days, so period in years:

$P=\frac{594}{365}$

P = 1.63 years

Calculating total mass:

$a^{3}=(M_{total})P^{2}$

$M_{total}=\frac{a^{3}}{P^{2}}$

$M_{total}=\frac{1.7^{3}}{1.63^{2}}$

$M_{total}=$ 1.85

The total mass of the two-object system is 1.85 mass units.

3 0

3 years ago

When a metal bonds with a nonmetal, they form a(n)

MArishka [77]

I believe it would be B.

5 0

4 years ago

gabi has plans with her friends to go to a concert on her birthday in 4 days. she is so excited that she wants to know how many

Lapatulllka [165]

Answer:

First we have to find how many seconds are there in a day which is 86,400 then multiply 86,400 and 4 which equals 345,600

hope this helps

have a great day!

7 0

3 years ago

Read 2 more answers

Where is the most of the liquid freshwater on earth located?

iren2701 [21]

Not sure but i will say D

6 0

3 years ago

Read 2 more answers

One end of an elastic cord is fastened to a steel beam. A metal weight with a mass of 68 kg is attached to the other end of the

Vika [28.1K]

Hi there!

We can use IMPULSE to solve.

Recall impulse:

$I = \Delta p = m\Delta v = m(v_f - v_i)$

Begin by calculating the impulse. Assuming up to be the + direction, and down to be the - direction.

$I = 68(11 - (-14)) = 68 \cdot 25 = 1700 kg\frac{m}{s}$

Now, we can calculate force using this value:

$I = F \cdot t\\\\F = \frac{I}{t}\\\\F = \frac{1700}{0.85} = \boxed{2000 N}$

The weight experiences a net force of 2000N UPWARDS.

4 0

3 years ago