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Helga [31]
4 years ago
13

What sequence shows electromagnetic waves arranged from shorter to longer wavelengths ?

Physics
1 answer:
timama [110]4 years ago
7 0

so from what i was looking at i think the answer is d because The shorter the wavelength, the higher measure of vitality it produces.So the request is D. Bright beams, Visible light, Infrared, and Microwaves.


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A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the dista
sleet_krkn [62]
<h2>The velocity of car was m m/s </h2>

Explanation:

When the car skids , its centripetal force is provided by frictional force .

Here centripetal force F = \frac{mv^2}{r}

here v is the velocity of car and r is the radius of the curve .

The frictional force f = μ R

here μ is the coefficient of kinetic friction and R is normal reaction

Thus f =  m g

On horizontal road R = mg

Thus F = f  at the time of skid .

Thus v = \sqrt{\mu rg}

= \sqrt{0.29x23.74x10} = 9 m/s

3 0
3 years ago
The compass of an airplane indicates that it is headed due north and its airspeed indicator shows that it is moving through the
yarga [219]

Answer:

Airplane speed relative to the ground is 260 km/h and θ = 22.6º  direction from north to east

Explanation:

This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.

Let's take the north direction with the Y axis and the east direction as the X axis

         Vy = 240 km / h            airplane

         Vx = 100 Km / h              wind

a) See the annex

Analytical calculation of the magnitude of the speed and direction of the aircraft

         V² = Vx² + Vy²

         V = √ (240² + 100²)

         V = 260 km/h

Airplane speed relative to the ground is 260 km/h

         Tan θ = Vy / Vx

         tan θ = 100/240

         θ = 22.6º

           

Direction from north to eastb

b) What direction should the pilot have so that the resulting northbound

          Vo = 240 km/h      airplane

          Vox = Vo cos θ

          Voy = Vo sin  θ

          Vx = 100 km / h      wind

To travel north the speeds the x axis (East) must add zero

         Vx -Vox = 0

         Vx = Vox = Vo cos θ

         100 = 240 cos θ

          θ = cos⁻¹ (100/240)

          θ = 65.7º

North to West Direction

The speed in that case would be

           V² = Vx² + Vy²

To go north we must find Vy

          Vy² = V² - Vx²

          Vy = √( 240² - 100²)

          Vy = 218.2 km / h

8 0
4 years ago
Describe the formation of the land, the atmosphere, and the oceans of earth
Firlakuza [10]
Land: Tectonic plate movement under the Earth can create landforms by pushing up mountains and hills. Erosion by water and wind can wear down land and create landforms like valleys and canyons. ... Landforms can exist under water in the form of mountain ranges and basins under the sea.

Atmosphere: (4.6 billion years ago)
As Earth cooled, an atmosphere formed mainly from gases spewed from volcanoes. It included hydrogen sulfide, methane, and ten to 200 times as much carbon dioxide as today's atmosphere. After about half a billion years, Earth's surface cooled and solidified enough for water to collect on it.

Ocean: After the Earth's surface had cooled to a temperature below the boiling point of water, rain began to fall—and continued to fall for centuries. As the water drained into the great hollows in the Earth's surface, the primeval ocean came into existence. The forces of gravity prevented the water from leaving the planet.
7 0
3 years ago
the force between a planet and a spacecraft is 1 million newtons. whst will the force be iv the spacecraft moves to halfg its or
dybincka [34]

The forces of gravity between two objects are inversely proportional to
the square of the distance between them.  So reducing the distance
by 1/2 means increasing the gravitational force by 2² = 4 times. 
The 1 million newtons becomes 4 million newtons.

Note that this does NOT mean the satellite's altitude above the surface.
When you're calculating gravitational forces, it's the distance between
the centers of the objects.  So the question is a meaningful exercise
only if we use the distance between the satellite and the planet's center.


6 0
3 years ago
Coulomb’s Law explains which of the following
Travka [436]
The force of attraction or repulsion between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them and acts along the line joining the two charges . F=k Q1Q2/r^2
5 0
3 years ago
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