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Juliette [100K]
3 years ago
15

An electric field is established by applying a potential difference to the plates. it is found that a field of strength e0 will

cause the droplet to be suspended motionless. write an expression for the droplet's charge q. let g be the acceleration due to gravity.
Physics
1 answer:
Citrus2011 [14]3 years ago
4 0
When the particle is suspended motionless its weight is in equilibrium with the force applied on through the electric field. Thus 
mg=qE
From this equality we can deduce the charge of the droplet necessary for the particle to stay suspended:
q= mg/E
where m is its mass and E is the electric field that is applied.
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