t1 = √2h1/g = √2*0.5/9,8 = 0.319 sec
t2 = √2h2/g = √2*1.0/9,8 = 0.451 sec
In which t = times for the vertical movement
h = height
g= gravity (we use standardized measurement of 9.8)
d1 = 1*0.319 = 0.319 m
d2 = 0.5*0.451 = 0.225 m
in which d = Horizontal distance
ratio
= di : d2
= 0.319 : 0.225
= 3.19 : 2.25
If a problem says the acceleration is some positive value than solve using that value, a negative acceleration is said to be deceleration. E.g. a car decelerating at 10 m/sec can be said to be accelerating at -10 m/sec.
If a problem states decelerates at A, then use -A for acceleration in the classic equations which are for acceleration. If a problem says accelerates at a negative value like -A the use -A as the value for acceleration, it can also be said to be decelerating at A.
Answer:
a) ω=n
b) V = R*n
c) a = 0
d) 
Explanation:
Angular velocity is given by the derivative of θ:
ω = n
Linear Velocity will be:
V = ω*R = n*R
Tangential acceleration will be the derivative of the linear velocity. Since velovity is constant:
a = 0
Radial acceleration is given by:

Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
<h3>What is force of inertia?</h3>
Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.
Given infroamtion-
The passengers are facing forward in the direction that the train is moving.
The train comes to a sudden stop.
Lets see what happens step wise-
- Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.
- Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.
- Thus all the passenger will tend to move in the direction as they are still travelling.
Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
Learn more about the force of inertia here;
brainly.com/question/10454047