Answer:
40.8g of sodium sulfate must be added
Explanation:
The reaction of barium nitrate, Ba(NO₃)₂ with sodium sulfate, Na₂SO₄ is:
Ba(NO₃)₂ + Na₂SO₄ → 2 NaNO₃ + BaSO₄(s)
That means, for a complete reaction of an amount of barium nitrate you must add the same amount in moles of sodium sulfate. To solve this problem we need to convert the mass of barium nitrate to moles = Moles of sodium sulfate that must be added:
<em>Moles Ba(NO₃)₂ -Molar mass: 261.3g/mol-:</em>
75g * (1mol / 261.3g) = 0.287 moles = Moles Na₂SO₄
<em>Mass Na₂SO₄ -Molar mass: 142.04g/mol-:</em>
0.287 moles * (142.04g / mol) =
<h3>40.8g of sodium sulfate must be added</h3>
We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of

we have to dilute??
It's simple.

Using a periodic table we can find the molar mass of


Then

now we can replace it


Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M
There are several severe weather events that occur due to cold fronts. The reason being is because winds will move towards each other along the front. The angle of a cold front is also greater than that of the other types of fronts, which creates more lift in the atmosphere vertically
Answer:
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Thankyou for points!!!!!!!!
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