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kicyunya [14]
3 years ago
14

Calculate the mass of butane needed to produce 60.6 g of carbon dioxide.

Chemistry
1 answer:
12345 [234]3 years ago
3 0

Answer:

You take the mass of carbon dioxide, 56.8g, divide by its molar mass, 44.01g/mol, to produce the moles of carbon dioxide. This is multiplied by the molar ratio of butane/CO2, (2/8) = 1/4, which gives the moles of butane required to produce the carbon dioxide.

Explanation:

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Answer:

The mass of P₄O₁₀ (s) formed is 471.03 g

Explanation:

4PH₃(g) + 8O₂(g) →  P₄O₁₀ (s)  + 6H₂O (g)

This is the ballanced equation.

Every 4 moles of phosphine, 1 mol of tetraphosphorus decaoxide is generated.

Moles of PH₃ = Mass PH₃ / Molar mass PH₃

Moles PH₃ = 225 g / 33.9 g/m

Moles PH₃ = 6.63 moles

So the rule of three, will be:

If 4 moles of PH₃ generate 1 mol  P₄O₁₀

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