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Anton [14]
3 years ago
13

What is the magnitude of g at a height above Earth's surface where free-fall acceleration equals 6.5m/s^2?

Physics
1 answer:
Tom [10]3 years ago
4 0

The magnitude of 'g' at a place is expressed in terms of
the acceleration due to gravity.

You have said that the gravitational acceleration at that place
is 6.5 m/s².  So THAT's the magnitude of 'g' right there.

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A very long straight current-carrying wire produces a magnetic field of 20 mt at a distance d from the wire. to measure a field
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The distance covered is 4d.

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We know that

the magnetic field is inversely proportional to distance.

\dfrac{B_1}{B_2} = \dfrac{D_2}{D_1}

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D_2 = 4d

To learn more about distance with the given link

brainly.com/question/15172156

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