Answer:
a
Explanation:
its electron arrangements is 9
Answer:
From the given variable values, we can calculate the density of the rock sample to be = 10750_Kg/m^3
Explanation:
To solve this question, we recollect that density is the mass per unit volume of a substance and the SI unit of density is Kg/m^3 with symbol
ρ
The given variables are as follows
mass of rock sample = 8.6g
The volume displaced in the graduated cylinder is
(Final volume level of the cylinder) - (initial volume level of the cylinder)
13.6ml - 12.8 ml= 0.8ml = volume of the rock sample
Therefore, density = 8.6/0.8 = 10.75g/ml = or 1000×10.75 Kg/m^3 =10750Kg/m^3
Density of the rock sample is 10750Kg/m^3
Answer:
TiCl2
Explanation:
Mass of the chloride of titanium= 1.31 g
Mass of titanium= 0.528 g
Therefore mass of chlorine = 1.31-0.528 = 0.782 g
To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.
Ti- 0.528/48 = 0.011, Cl- 0.782/35.5 = 0.022
Ti- 0.011/0.011 , Cl- 0.022/0.011
Ti- 1, Cl-2
Hence the required empirical formula is TiCl2