Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225
<span>mols KOH = 3.00 x 0.150 = 0.450 </span>
<span>specific heat solns = specific heat H2O = 4.18 J/K*C </span>
<span>CuSO4 + 2KOH = Cu(OH)2 + 2H2O </span>
<span>q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T </span>
<span>q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) </span>
<span>dHrxn in J/mol= q/0.225 mol CuSO4 </span>
<span>Then convert to kJ/mol
</span>
Osmotic pressure is the pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis.
That can be mathematical computed from the expression:
Osmotic pressure=C×R×T
Where,
C= Concentration
R=Gas constant
T=Temperature
Concentration=Number of moles of solute/Volume(L)
=0.005*1000/100
=0.05
R= 0.08206 atm L/mol K
T=25+273
=298
Osmotic pressure= 0.05×0.08206×298
=1.2 atm
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<h3>
Answer:</h3>
pH = 8.66
<h3>
Explanation:</h3>
- The pH refers to the acidity or alkalinity of a solution.
- It is calculated by getting the negative logarithm of Hydrogen ions concentration.
In this case;
we are given [OH⁻] as 4.6 x 10^-6 M
We are required to calculate the pH
We need to know that;
pH + pOH = 14
pOH = -log[OH⁻]
To get the pH we can calculate the pOH first,
pOH = -log[4.6 x 10^-6 M]
= 5.34
but, pH + pOH = 14
Therefore, pH = 14 - pOH
= 14 - 5.34
= 8.66
Therefore, the pH of the solution is 8.66
