Question

A horizontal spring has one end firmly attached to a wall and the other end attached to a mass. The mass can slide freely on a smooth, horizontal surface with no friction. When the mass is at the x = 0.020-m position so that the spring is stretched by 0.020 m, what is true about the force exerted on the mass by the spring?

Answer 1

Answer:

The force increases in magnitude proportionally with increasing position of the mass.

The force points in the negative x-direction.

The position of the mass is the same magnitude of the distance stretched the spring.

Explanation:

$F_s=\frac{1}{2}*K*x^2$