All categories

3 years ago

:3333333333333333333333

Physics

1 answer:

elixir [45]3 years ago

3 0

Answer:

Cannot see all the answer choices but, when pressure goes up, volume goes down. So your best bet is to choose the graph that has a downward slant.

Explanation:

You might be interested in

A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground. When he is 10 feet fr

harina [27]

Answer:

$\frac{25}{3}ft/s$

Explanation:

Height of man= 6ft

Height of light=1 5ft

Let BC=x and CD=y

BD=x+y

Triangle ABD and ECD are similar

When two triangles are similar then the ratio of their corresponding sides are equal

$\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{15}{6}=\frac{x+y}{y}$

$\frac{5}{2}=\frac{x+y}{y}$

$5y=2x+2y$

$5y-2y=2x$

$3y=2x$

Differentiate w.r.t t

$2\frac{dx}{dt}=3\frac{dy}{dt}$

We have $\frac{dx}{dt}=5ft/s$

Substitute the value then we get

$2\times 5=3\frac{dy}{dt}$

$\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s$

Rate at which the tip of shadow is moving= $\frac{dx}{dt}+\frac{dy}{dt}$

Rate at which the tip of shadow is moving= $5+\frac{10}{3}=\frac{15+10}{3}ft/s$

Rate at which the tip of shadow is moving= $\frac{25}{3}ft/s$

5 0

3 years ago

1 hr 16 minutes equal how many minutes ?

Len [333]

Answer:

76 minutes.

Explanation:

There are 60 minutes in an hour + 16 minutes= 76 minutes.

4 0

3 years ago

Mimas, a moon of Saturn, has an orbital radius of 1.62 × 108 m and an orbital period of about 23.21 h. Use Newton’s version of K

Drupady [299]

Answer:

$3.60432\times 10^{26}\ kg$

Explanation:

a = Orbital radius = $1.62\times 10^8\ m$

T = Orbital period = 23.21 hours

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Kepler's third law we get

$M=\frac{4\pi^2a^3}{GT^2}\\\Rightarrow M=\frac{4\pi^2\times (1.62\times 10^8)^3}{6.67\times 10^{-11}\times (23.21\times 3600)^2}\\\Rightarrow M=3.60432\times 10^{26}\ kg$

From the given data the mass of Saturn is $3.60432\times 10^{26}\ kg$

8 0

3 years ago

Indique onde em quantos metros o rapaz chegará com as seguintes condições: S0 = 0 a) v = 3 m/s e t = 2 s b) v = 2 m/s e t = 3,5

Naily [24]

Answer:

I will answer in English.

Here we will use the relation

Velocity*time = distance

So:

a) velocity = 3m/s

time = 2s

Distance = 3m/s*2s = 6m

b) velocity = 2m/s

time = 3.5s

Distance = 2m/s*3.5s = 7m

c) velocity = 10m/s

time = 0.5s

Distance = 10m/s*0.5s = 5m

d) velocity = 4m/s

time = 2.5s

Distance = 4m/s*2.5s = 9m

e) velocity = 1.5m/s

time = 5s

Distance = 1.5m/s*5s = 7.5m

8 0

3 years ago

The temperature of water in a beaker is 45°C. What does this measurement represent

andrezito [222]

Based on my information, this would actually be representing "the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be $45$ °C, this would make more sense for this to be representing as <span>the average kinetic energy of water particles.</span>

3 0

3 years ago

Read 2 more answers