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True [87]
3 years ago
7

Describe the type of radioactive emission produced from the decay of carbon-14 to nitrogen-14 and predict its reaction to an ele

ctric field.
Physics
2 answers:
erastova [34]3 years ago
8 0

Answer:

A beta emission(negatron)

Explanation:

1. A negatron resembles an orbital electron. It is represented as β⁻.

A negatron has a mass number of 0 but with a charge of -1

The decay of C-14 to N-14 can be depicted below:

¹⁴₆C → ¹⁴₇N + ₋₁⁰e

Both the mass number and atomic number is balanced according to the reaction.

2. In an electric field, the emission produced would be deflected towards the positive pole because it is negatively charged.

Harlamova29_29 [7]3 years ago
8 0

Beta radioactive emission

During this radioactive decay, Beta charges are released. These negative particles tend to be attracted to the positive plate in the electric field.

The radioactive decay of C-14 produces a N-14 atom through the emission of Beta particles.

The Beta particles are negatively charged and would be attracted to the positive plate in the electric field because according to law of charges, like charges will tend to repel each other while unlike charges will attract each other.

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The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
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A) 5.0\cdot 10^{-11} m

The energy of an x-ray photon used for single dental x-rays is

E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J

The energy of a photon is related to its wavelength by the equation

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

Re-arranging the equation for the wavelength, we find

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m

B) 2.0\cdot 10^{-11} m

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m

4 0
3 years ago
What is the speed of light in meters per second?
MAXImum [283]
The answer is approximately 2.998e+8
3 0
3 years ago
A proton initially at rest is accelerated by a uniform electric field. The proton moves 5.62 cm in 1.15 x 10^-6 s. Find the volt
krok68 [10]

Answer:

49.85 V

Explanation:

u = 0, s = 5.62 cm, t = 1.15 x 10^-6 s

Let the electric field is E and voltage is V.

Use second equation of motion

s = ut + 1/2 a t^2

5.62 x 10^-2 = 0 + 0.5 a x (1.15 x 10^-6)^2

a = 8.5 x 10^10 m/s^2

m x a = q x E

E = m x a / q

E = (1.67 x 10^-27 x 8.5 x 10^10) / (1.6 x 10^-19)

E = 887.19 V/m

V = E x s

V = 887.19 x 5.62 x 10^-2 = 49.85 V

4 0
4 years ago
A 2.00-gram air inflated balloon is given an excess negative charge, q1 = -3.25 × 10-8 C, by rubbing it with a blanket. It is fo
Llana [10]

Answer:

The rod`s charge must be positive,  because the gravity force is pointing downwards and the electrostatic force must be pointing upwards (in order to balance the gravity force)

The charge is q_2 = 1.667 times 10^(-7) C

Explanation:

F_e = F_g

where F_g = m g and F_e= (1/4 pi e_0)*(q_1*q_2)/d^2,

please see the file attached for more details.

Download pdf
3 0
3 years ago
An airplane flies a distance of 650 km at an average speed of 300km/h. how much time did the flight last
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X = v * t
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