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Darina [25.2K]
3 years ago
11

18) A package is oscillating on a spring scale with a period of 4.60 s. At time t = 0.00 s the package has zero speed and is at

x = 8.30 cm. At what time after t = 0.00 s will the package first be at x = 4.15 cm? A) 0.575 s B) 0.767 s C) 1.15 s D) 1.30 s E) 1.53 s
Physics
1 answer:
monitta3 years ago
7 0
What math level is this
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To simulate deafness, put ear plugs or cotton balls into your ears and put your hands over your ears to block out all sound. Des
yulyashka [42]

Just so you know, total deafness is quite different than partial deafness.

Partial deafness can be any number of things. It can be an inability to make out the contents of high notes (notes with high frequencies and few harmonics).

Partial deafness can be the inability to hear low notes. I only know one person who suffers from that.

Your response to speech is quite different. Usually you have to have people look right at you. Lip reading is an art. Most deaf people between what they partially hear and lip reading can make out about 1/2 of what is said. Guessing usually takes care of the rest. Course you can get everything all muddled by guessing.

It does change your way of life. The TV is often turned up high enough that people living 4 houses down can list to the 6 o'clock news when you do.

Music is hard to make out. The overtones are lost.

Earphones have very tinny sound.

People are not as enjoyable as they once were.

6 0
3 years ago
If the northern hemisphere were tilted 90° towards the sun which location would be warmer in summer the Arctic Circle or Florida
nikdorinn [45]
Florida would be warmer.
7 0
3 years ago
A 16.7 kg block is dragged over a rough, horizontal surface by a constant force of 132 N acting
Alisiya [41]

The magnitude of the work done by the force of friction is 1045.68 joules

Explanation:

Work done = force × distance

  • Work done by friction force (W) = friction force (F) × distance (d)
  • Friction force (F) = coefficient of  kinetic friction (μ) × normal reaction force (R)

A 16.7 kg block is dragged over a rough, horizontal surface by a constant force of 132 N acting  at an angle of 25.8. above the horizontal. The block is displaced 57,8 m, and the coefficient of  kinetic friction is 0.229

To find the normal reaction force of the block distribute The constant force into two component, horizontal component of 132 cos(25.8°) and vertical component 132 sin(25.8°), Then equate ∑vertical forces by 0 to find R

The weight of the block = mg, where m is its mass and g is 9.8 m/s²

→ ∑Vertical forces = R + 132 sin(25.8°) - mg

→ ∑Vertical forces = R + 132 sin(25.8°) - (16.7)(9.8)

→ ∑Vertical forces = R - 106.2

Equate it by 0

→ R - 106.2 = 0 ⇒ add 106.2 to both sides

→ R = 106.2 N

Now let us find the friction force

→ F = μ R

→ μ = 0.229

→ F = 0.229 (106.2) = 24.3198 N

Let us calculate the work don by the force of friction

→ W = F × d

→ d = 57.8 meters

→ W = 24.3198 × 57.8 = 1045.68 joules

The magnitude of the work done by the force of friction is 1045.68 joules

Learn more:

You can learn more about force of friction in brainly.com/question/6217246

LearnwithBrainly

6 0
3 years ago
A state highway was constructed over wetlands. The state obtained a permit to fill the existing wetlands in accordance with the
bixtya [17]

Answer:

Environmental mitigation

Explanation:

Environmental migitation is related environmental industry to describe  impacts to the  wetland, endangered species, archeological site, paleontological site or historic structure.

This  Act mainly focus on action of reducing the severity, seriousness, or painfulness to the environment.

According Clean Water Act in 1972, they agreed to create a another wetland for state highway which was constructed over wetlands.

8 0
3 years ago
The velocity component with which a projectile covers certain horizontal distance is maximum at the moment of? a) Hitting the gr
Crazy boy [7]
A) hitting the ground
3 0
4 years ago
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