1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rjkz [21]
4 years ago
9

A circuit is supplied with 60 VDC and contains two series resistors with values of 100 and 400 . What is the total current in th

e circuit?
A. 2 A
B. 0.82 A
C. 1.2 A
D. 0.12 A

What circuit quantity is measured by connecting a meter's test leads in series with an energized component?
A. Resistance
B. Power
C. Voltage
D. Current
Physics
1 answer:
scoundrel [369]4 years ago
6 0

When resistors are connected in series, they act like
a single resistor whose resistance is their sum. 

100 ohms and 400 ohms, connected in series, look like
a single resistor of 500 ohms.

           Current = (voltage) / (resistance)

                        = (60 volts) / (500 ohms) = 0.12 A.
________________________
<span>
Current is measured by connecting a meter in series
with an energized component.  In other words, a break
is made in the circuit, the meter is connected in the break,
and the current to be measured literally flows through the meter.</span>

You might be interested in
Light refracts because
NeTakaya

Answer:

it travels at a different refractive index.

Explanation:

for example when light travels into water, it slows down, causing it to continue to travel at a different or another angle or direction. hope this helped!

5 0
4 years ago
Read 2 more answers
If I = 2.0 A in the circuit segment shown below, what is the potential difference VB - VA?
Tom [10]

Answer:

10 V

Explanation:

The potential difference between two points is the amount of work required to carry a unit charge from one point to the other point. This would result in a potential difference between this two points.

The difference between the potential across two points B and A is V_{BA}=V_B-V_A

From the image attached:

V_B-V_A=10-10I+20\\\\But\ I = 2A,hence:\\\\V_B-V_A=10-10(2)+20\\\\V_B-V_A=10-20+20\\\\V_B-V_A=10\ V

7 0
3 years ago
Cany anyone teach me how to use the vernier callipers?
luda_lava [24]
Place the object in between the two jaws such that they touch opposite ends of the object making sure the object is held firmly but don’t press too tight. If you need to measure an internal diameter, then insert the upper jaws in to the cavity and open them till they touch the sides. Tighten the locking screw to hold the jaws in position.

Note the position of the vernier scale zero on the main scale. The main scale reading is the division just before where the zero mark of the vernier scale is aligned. So is the zero mark aligns just after the fifth division between 3 and 4 the main scale reading is then 3.5.

The next step is to take the vernier scale reading. To do this find the mark on the vernier scale which lines up perfectly with a mark on the main scale. The vernier reading can then be found by multiplying the least value of the vernier scale with the number of divisions till that mark. For example if the least value is 0.01 mm and the 7thmark of the vernier scale is lined up perfectly then the vernier scale reading is 7 x 0.01 = 0.07.

The final step is to add the main scale and vernier readings to get the final measurement. For example 3.5 + 0.07 = 3.57 mm.

5 0
3 years ago
A hockey puck is struck so that it slides at a constant speed and strikes the far side of the rink, 58.2 m away. The shooter hea
DENIUS [597]

Answer:

v = 33.66 m/s

Explanation:

Let hockey puck is moving at constant speed v

so here we have

d = vt

so time taken by the puck to strike the wall is given as

t = \frac{58.2}{v}

now time taken by sound to come back at the position of shooter is given as

t_2 = \frac{58.2}{340}

t_2 = 0.17s

so we know that total time is 1.9 s

1.9 = t + t_2

1.9 = t + 0.17

1.9 - 0.17 = t

t = 1.73 s

now we have

1.73 = \frac{58.2}{v}

v = 33.66 m/s

7 0
3 years ago
A parallel RLC circuit contains an inductor with a value of 400 microhenries and a capacitor with a value of 0.3 microfarads wha
ipn [44]

Answer:

The resonant frequency of this circuit is 14.5 kHz.

Explanation:

Given that,

Inductance of a parallel LCR circuit, L=400\ \mu H=400\times 10^{-6}\ H

Capacitance of parallel LCR circuit, C=0.3\ \mu F=0.3\times 10^{-6}\ F

At resonance the inductive reactance becomes equal to the capacitive reactance. The resonant frequency is given by :

f=\dfrac{1}{2\pi \sqrt{LC} }

f=\dfrac{1}{2\pi \sqrt{400\times 10^{-6}\times 0.3\times 10^{-6}} }

f=14528.79\ Hz

or

f = 14.5 kHz

So, the resonant frequency of this circuit is 14.5 kHz. Hence, this is the required solution.

4 0
3 years ago
Other questions:
  • Describe the cyclic patterns of lunar phases and eclipses of the Sun and moon.
    8·1 answer
  • SomeOne please help me will give BRAILIEST!!!!!!!!
    5·2 answers
  • What is the displacement for a driver who travels 10 km to get to a point that is 4 km from his starting point?
    5·1 answer
  • Number of electrons in Na
    14·2 answers
  • A 100 N box sits on a 30 degree incline. If the static coefficient of friction is 0.1, what is the magnitude of the static frict
    6·1 answer
  • The pedals on a bicycle give a mechanical advantage by allowing you to turn the pedals a __________ distance to turn the _______
    8·1 answer
  • Deb is planning to paint a wall of her house that has two regular hexagonal windows. Painting the wall costs $1.75 per square fo
    12·1 answer
  • A 39.5 kg child stands at the center of a 125 kg playground merry-go-round which rotates at 3.10 rad/s. If the child moves to th
    13·1 answer
  • A car starts from rest at a stop sign. It accelerates at 4.0 m/s^2 for 3 seconds, coasts for 2 s, and then slows down at a rate
    9·2 answers
  • When discussing Newton's laws of motion which terms do people most likely use when talking about Newton's third law of motion
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!