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rjkz [21]
4 years ago
9

A circuit is supplied with 60 VDC and contains two series resistors with values of 100 and 400 . What is the total current in th

e circuit?
A. 2 A
B. 0.82 A
C. 1.2 A
D. 0.12 A

What circuit quantity is measured by connecting a meter's test leads in series with an energized component?
A. Resistance
B. Power
C. Voltage
D. Current
Physics
1 answer:
scoundrel [369]4 years ago
6 0

When resistors are connected in series, they act like
a single resistor whose resistance is their sum. 

100 ohms and 400 ohms, connected in series, look like
a single resistor of 500 ohms.

           Current = (voltage) / (resistance)

                        = (60 volts) / (500 ohms) = 0.12 A.
________________________
<span>
Current is measured by connecting a meter in series
with an energized component.  In other words, a break
is made in the circuit, the meter is connected in the break,
and the current to be measured literally flows through the meter.</span>

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7 0
4 years ago
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the
Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

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Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

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The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

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