Answer:
KE = 0.262 J
Explanation:
given data
rifle with mass Mr = 2.57 kg
bullet with mass Mb = 3.65 g
velocity relative to the ground Vb = 318.4 m/s
solution
we get here final KE of rifle that is express as
KE = 0.5 × Mr × (Vr)² ..............1
here Vr is
Mb × Vb = Mr × Vr .........2
put here value
3.65 × 
× 318.4 = 2.57 × Vr
Vr = 0.452 m/s
now put value in eq 1 we get
KE = 0.5 × 2.57 × (0.452)²
KE = 0.262 J
Left:
2*g-TL=2*aL
aL=α*0.231
therefore
TL=2*(g-α*0.231)
Right:
TR-1.4*g=4*aR
aR=α*0.272
therefore
TR=1.4*(g+α*0.272)
Wheels:
TL*0.231-TR*0.272=
(2*0.231^2+2.3*0.272^2)*α
combine and solve for α
Answer:
at its centre
Explanation:
The centre of gravity is a point inside the body where entire weight os the body is said to be concentrated. For geometrical symmetric bodies it lies at the geometric centre of the body.
The base ball is a spherical body, so its centre of gravity lies at its centre.
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