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Anna007 [38]
3 years ago
12

PLEASE HELP!!! Which of John Dalton's contributions are present in the modern atomic model and which were eventually disproven a

nd thus are not part of the modern model??? If you have any questions please don't ask in the answer box.
Chemistry
1 answer:
Yanka [14]3 years ago
5 0
1) All matter is made of atoms. Atoms are indivisible and indestructible.

2) All atoms of a given element are identical in mass and properties

3) Compounds are formed by a combination of two or more different kinds of atoms.

4) A chemical reaction is a rearrangement of atoms.

1 and 2 were proved wrong.
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I think the answer is 4.)Cumulonimbus but I'm not 100% sure
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Why are the bacterial endospores placed on the paper strip and not directly in the fermentation broth?
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4 years ago
Describe 3 characteristics of the carbon atom that makes possible the building of variety of biological molecules
Marianna [84]

3 characteristics of the carbon atom that makes possible the building of variety of biological molecules are:

• Carbon atoms can easily form covalent bonds with nitrogen, hydrogen, oxygen,  sulfur and with carbon. The bonds can be single, double or triple between the atoms. This combination of carbon with other elements and with itself results in the formation of huge number of biological molecules.

• The size of carbon atom is very small in comparison to most other atoms. Thus, the bond formed between two carbon atoms is quite short. And the shorter bonds are more stronger than the longer bonds between two atoms, that's why carbon bonds are stable at the different temperatures associated with life.

• Only carbon can form stable four covalent bonds with the other elements, which makes it versatile element to serve as the basic structural component, of the macro-molecules.

4 0
3 years ago
Write the formula and name of the compound formed from the following ionic interactions:
Ainat [17]

Answer:

Explanation:

a ) period 4 noble gas is krypton

isoelectronic with it are Sr ⁺² and Br⁻

compound is SrBr₂

b ) Period 3 noble gas is Argon

isoelectronic with it are Mg⁺² and O⁻²

compound is MgO

c)  2+ ion is the smallest with a filled d subshell is Zn⁺² , smallest halogen

is F⁻

compound is ZnF₂

d )   ions  from the largest and smallest ionizable atoms in Period 2

Li⁺ and  F⁻

compound is LiF

8 0
3 years ago
Rank and explain how the freezing point of 0.100 m solutions of the following ionic electrolytes compare. List from lowest freez
Elden [556K]

Answer:

The solutions are listed from the lowest freezing point to highest freezing point.

Mg₃(PO₄)₂ -  AlBr₃ - BeBr₂ -  KBr

Explanation:

Colligative property of freezing point, is the freezing point depression.

Formula is:

ΔT = Kf . m . i

Where ΔT = T° freezing pure solvent - T° freezing solution

Kf is the cryoscopic constant

m is molality and i is the Van't Hoff factor (number of ions, dissolved in solution)

In this case, T° freezing pure solvent is 0° because it's water, so the Kf is 1.86 °C/m, and m is 0.1 molal.

The i modifies the T° freezing solution. The four salts, are ionic compounds, so for each case:

BeBr₂  → Be²⁺  +  2Br⁻   i = 3

AlBr₃ →  Al³⁺  + 3Br⁻   i = 4

Mg₃(PO₄)₂  →  3Mg²⁺  +  2PO₄⁻³    i = 5

KBr →  K⁺  +  Br⁻   i = 2

Solution of Mg₃(PO₄)₂ will have the lowest temperature of freezing and the solution of KBr, the highest (always lower, than 0°).

8 0
3 years ago
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