Question

A charge of 25.0 nc is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4.00×104 n/c . what work is done by the electric force when the charge moves

Answer 1

Hello!

Work is equal to the change in KE or the negative change in PE. So if e field is directed vertically upward or in positive y direction and our charge is positive it’s going to move in direction of e field so then the work done by the e field is negative because it is losing potential energy the farther it moves upward away from field. Work=qed which is charge*e field*distance travelled.

Hope this helps! Any questions please ask! Thank you!!