2.01214904 × 10²² silver atoms are there in 3.74 g of silver
The most common isotope of silver has 60 neutrons, 47 protons, and 47 electrons. Silver is a soft metal with a glossy metallic luster under normal circumstances. It is exceedingly malleable and ductile (can be formed into a wire).
The molar mass of silver is as follows:
Molar mass of Ag = 107.8682 g/mol
The number of atoms in a molar mass is Avogadro’s number:
6.022140857 × 10²³
Therefore 3.8 g of silver contains 3.8 times 6.022140857 × 10²³ divided by 107.8682 that equals 0.03522818 times
6.022140857 × 10²³
= 2.01214904 × 10²² atoms.
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Answer:
3.94 × 10³ g
Explanation:
Step 1: Write the neutralization reaction
HClO₃ + NaOH = NaClO₃ + H₂O
Step 2: Calculate the moles of chloric acid that react
25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:
![25.5L \times \frac{3.86mol}{L} =98.4mol](https://tex.z-dn.net/?f=25.5L%20%5Ctimes%20%5Cfrac%7B3.86mol%7D%7BL%7D%20%3D98.4mol)
Step 3: Calculate the required moles of sodium hydroxide
The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.
Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles
The molar mass of NaOH is 40.00 g/mol.
![98.4mol \times \frac{40.00g}{mol} =3.94 \times 10^{3} g](https://tex.z-dn.net/?f=98.4mol%20%5Ctimes%20%5Cfrac%7B40.00g%7D%7Bmol%7D%20%3D3.94%20%5Ctimes%2010%5E%7B3%7D%20g)