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Elis [28]
3 years ago
8

The rigid link is supported by a pin at A and two A-36 steel wires, each having an unstretched length of 12 in. and cross-sectio

nal area of 0.0125 in2. Determine the force developed in the wires when the link supports the vertical load of 350 lb.
Physics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

Extension of the wire is not indicated

Explanation:

Young modulus (YM)= (stress/Strain); Tensile Stress/tensile Strain

=> YM *Strain =Stress=F/A; A is cross sectional area and F is the force

(YM * Strain * A)/36 =F (Force developed in each wire)

F = (350 *e*0.0125)/12

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The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the valu
djverab [1.8K]

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

5 0
3 years ago
Read 2 more answers
During a workout, the football players at State U ran up the stadium stairs in 61 s. The stairs are 130 m long and inclined at a
NeTakaya

Answer:

  P = 1097 Watt

Explanation:

given,

length of stairs, L = 130 m

inclination with horizontal,θ = 30°

mass of the football player = 105 Kg

time = 61 s

we know,

Power = \dfrac{work}{time}

Work = change in Potential energy

 h = L sin 30°

 h = 130 x 0.5

 h = 65 m

W = m g h

W = 105 x 9.8 x 65

W = 66885 J

now,

P = \dfrac{66885}{61}

  P = 1097 Watt

hence, the power output on the way is 1097 W

5 0
3 years ago
A vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west​
just olya [345]

Answer:

5 m/s

Explanation:

Given that,

A vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west​.

It is assumed to find the resultant velocity of the vehicle. Let east side is positive and west is negative. So,

v=v_1+v_2\\\\=20+(-15)\\\\=5\ m/s

Hence, the resultant velocity of the vehicle is equal to 5 m/s.

6 0
3 years ago
A basic physics question
Anna71 [15]
<h3>1)</h3>

No,kinetic energy cannot be negative since its given by KE=mv²,mass cannot be negative and the square of speed cannot b negative.

<h3>2)</h3>

Yes,any force opposing motion or displacement does negative work. They are often referred to as resistive forces (friction,air resistance,drag...)

<h3>3)</h3>

Nope it does not, it just forces the object to move in a circular path known as a centripetal force. It can accelerate an object by changing it's direction but not it's speed.

<h3>4)</h3>

No it cannot,If an object is sliding on the table (assuming it is not an incline), then most probably that normal force cancels out the weights effect or assuming there is an incline, it cancels the weight's y component.

<h3>5)</h3>

w = f.d.cos \alpha  = f.d.cos90 = 0

The work done is zero

<h3>6)</h3>

w = f.d.cos \theta = f.d.cos0 = f.d

The work is just the product of the magnitude of the force exerted and the displacement of the object.

<h3>7)</h3>

0 <  \theta < 90 \\ 1 < cos \theta < 0

<h3>Work is decreasing but positive</h3>

<h3>8)</h3>

\theta = 90 \\ cos \theta = cos90 = 0

<h3>Work is zero</h3>

<h3>9)</h3>

90 <  \theta < 180 \\ 0 < cos \theta <  - 1

<h3>Work is negative</h3>
3 0
2 years ago
A skier starts from rest at the top of a 40.8 m hill, skis down a 30 degree incline into a valley, and continues up a 32.5 m hig
Volgvan

Answer:

a. 28.27 m/s

b. 12.75 m/s

c. No

Explanation:

a.

The bottom

Ek = Ep

¹/₂ * m * v² = m * g * h₁

v = √ 2 * g * h₁  = √ 2 * 9.8 * 40.8 m

v = 28.27 m/s

b.

At the top

Ek = Ep

¹/₂ * m * v² = m * g * h₁

v = √ 2 * g * h₁  = √ 2 * 9.8 * (40.8 - 32.5) m

v = 12.75 m/s

c.

No in this case the axis is the same of the motion so, the angle doesn't affect the result

3 0
3 years ago
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