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Zigmanuir [339]
4 years ago
8

Draw one valid lewis structure (including all lone pair electrons and any formal charges) for ch3no2. Assume the atoms are arran

ged as shown below.

Chemistry
1 answer:
MAXImum [283]4 years ago
4 0

The lewis structure is drawn as

a) we first count the total number of valence electrons in the compound

b) then we give one pair of electrons in between each pair of bonded atoms

c) rest of the electrons are arranged around the side atoms to fullfill their octet

d) the electrons are rearranged to complete octet of maximum number of atoms

so the structure will be:


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<h2>Question:- </h2>

A solution has a pH of 5.4, the determination of [H+].

<h2>Given :- </h2>
  1. pH:- 5.4
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<h2>To find :- concentration of H+</h2>

<h2>Answer:- Antilog(-5.4) or 4× 10-⁶</h2>

<h2>Explanation:- </h2><h3>Formula:- pH = -log H+ </h3>

Take negative to other side

-pH = log H+

multiple Antilog on both side

(Antilog and log cancel each other )

Antilog (-pH) = [ H+ ]

New Formula :- Antilog (-pH) = [+H]

Now put the values of pH in new formula

Antilog (-5.4) = [+H]

we can write -5.4 as (-6+0.6) just to solve Antilog

Antilog ( -6+0.6 ) = [+H]

Antilog (-6) × Antilog (0.6) = [+H]

Antilog (-6)  = {10}^{ - 6} ,  \\ Antilog (0.6)  = 4

put the value in equation

{10}^{ - 6}   \times 4 = [H+] \\ 4 \times   {10}^{ - 6}  = [H+]

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