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Leya [2.2K]
3 years ago
14

HELP PLEASE!!!!!!!!

Chemistry
1 answer:
Ray Of Light [21]3 years ago
6 0
Reactant is the left side. 4+3=7
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If the volume occupied by 0.500 mol of nitrogen gas at 0°C is 11.2 L, then the volume occupied by 2.00 mol of nitrogen gas at th
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The  volume  occupied  by 2.00  moles of nitrogen  gas at  the same  temperature  and pressure  will be

 0.500  moles = 11.2 Liters
 what about 2 moles =? liters

by cross  multiplication

= 11.2 liters  x   2moles/ 0.500 moles  =  44.8  liters 
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The combustion of ________ has added great quantities of carbon dioxide to the atmosphere. Group of answer choices
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Answer:

Fossil fuels.

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Calculate the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 ml solution.
Lelechka [254]

Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liter}.

<h3>Molarity in this case</h3>

In this case, you have:

  • number of moles= 0.2 moles
  • volume= 100 mL= 0.1 L

Replacing in the definition of molarity:

molarity=\frac{0.2 mole}{0.1 L}

Solving:

<u><em>molarity= 2 </em></u>\frac{moles}{liter}

Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 \frac{moles}{liter}.

Learn more about molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

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How could Mendeleev predict the properties of elements that had not yet been discovered?
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It was the element of aluminium where they predict their properties <span />
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