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Lorico [155]
2 years ago
15

After it was discovered, astronomers predicted Uranus's orbit using Newton's laws of motion and gravity, which had worked extrem

ely well for all of the other planets. To their surprise, they found that their observations of Uranus's motion through the sky did not match their predictions. Which of the following would be the most logical next step?
A. Check for other previously undiscovered factors that might alter Uranus's orbit while still allowing it to obey Newton's laws of motion and gravity.
B. Newton's laws of motion and gravity must be modified to match the data.
C. Newton's laws of motion and gravity have been falsified, so they should be scrapped in favor of a completely new hypothesis.
D. If the data doesn't match Newton's laws of motion and gravity, then the data must be bad, so this finding should be disregarded.
Physics
1 answer:
kotykmax [81]2 years ago
4 0

Answer:

A. Check for other previously undiscovered factors that might alter Uranus's orbit while still allowing it to obey Newton's laws of motion and gravity.

Explanation:

Uranus behaved in a way that Newton's laws of motion could not explain. But this law predicted very well the behavior of other planets, so it could not be totally wrong or discarded, so it was decided to look for whether there was a planet beyond Uranus, which would alter its movement. The search was done and this is how <u>Neptune </u>was discovered, and by adding the attraction that Neptune would have on Uranus, its orbit could be calculated correctly by Newton's laws of motion.

Since Newton's law of gravitation had worked so well it was more likely that there were unknown factors that would alter his movement, rather than the laws no longer working or the data being wrong.

Later Newton's law of gravitation was modified by Einstein to take into account the effects of relativity. But Newton's laws work very well to describe the solar system.

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Which option is an example of reflection?
katovenus [111]

Answer:

A

Explanation:

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2 years ago
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The diagram below shows some waves traveling along a rope.
Harrizon [31]

-- Well first of all, the waves are <em>transverse waves</em>.  The fibers in the rope, and the hand that generates the waves, are moving up and down, but the wave is moving to the right, towards the wall.  These directions are perpendicular.

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3 0
3 years ago
La trayectoria de vuelo del helicóptero cuando despega desde A esta definida por las ecuaciones x=2t^2 m y y=0.04t^3 m, donde t
Yuri [45]

Answer:

The flight path of the helicopter when it takes off from A is defined by the equations x = 2t ^ 2 m and y = 0.04t ^ 3 m, where t is the time in seconds. Determine the distance the helicopter is from point A and the magnitudes of its speed and acceleration when t = 10 s

Explanation:

Given that,

The path curve are

x = 2t²

y = 0.04t³

Distance from A. When t = 10s

The position on the x axis at t=10s is

x = 2t²

x = 2×10² = 200m

The position on y axis at t= 10s is

y = 0.04t³

y = 0.04 ×10³ = 40m

So, the plane it at (200,40) and it started for (0,0)

From geometry we can find distance between the two point using

D = √(x2-x1)² + (y2-y1)²

D = √(200-0)²+(40-0)²

D = √200²+40²

D = 203.96m

So, the distance is approximately 204m

b. The magnitude of the speed.

Speed is give as the differentiation of distance

So, for x curve, at t =10

Vx = dx/dt = 4t

Vx = 4×10 = 40m/s

Also, for y axis at t=10

Vy = dy/dt = 0.12t²

Vy = 0.12×10² = 12m/s

Then, the velocity at 10s is

V = √(Vx²+Vy²)

V = √40²+12²

V = 41.76m/s

The velocity helicopter at t=10s is 41.76m/s

c. The acceleration at t=10s?

We need to find acceleration of the curve and it is given as

a = d²x/dt²

So, for x axis at t=10

ax= d²x/dt² = 4

ax = 4m/s²

Also, for y axis at t=10

ay= d²y/dt² = 0.24t

ay = 0.24 ×10 = 2.4m/s²

Then, the magnitude of acceleration at t=10s is

a = √(ay²+ax²)

a = √2.4²+ 4²

ay = 4.66m/s²

The acceleration of the helicopter at t=10s is 4.66m/s²

4 0
3 years ago
Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 170 V. An electron ent
dmitriy555 [2]

To solve this problem it is necessary to apply the concepts related to energy as a function of voltage, load and force, and the definition of Force given by Newton in his second law.

By definition we know that force is equal to

F= ma

Where,

m = mass (at this case of an electron)

a = Acceleration

But we also know that the Energy of an electric object is given by two similar definitions.

1) E= \frac{F}{q}

Where,

F= Force

q = Charge of proton/electron

2) E = \frac{V}{d}

V = Voltage

d = Distance

Equating and rearrange for F,

\frac{F}{q} = \frac{V}{d}

F = \frac{Vq}{d}

The two concepts of force can be related to each other, then

ma = \frac{Vq}{d}

Acceleration would be,

a = \frac{Vd}{dm}

Replacing with our values we have that the acceleration is

a = \frac{Vq}{dm}

a = \frac{(170)(1.6*10^{-19})}{(2*10^{-2})(9.1*10^{-31})}

a = 1.49*10^{15}m/s^2

Now through the cinematic equations of motion we know that,

V_f^2-V_i^2 = 2ax

Where,

V_f = Final velocity

V_i = Initial velocity

a = Acceleration

x = Displacement

Re-arrange to find v_f,

v_f = \sqrt{v_i^2+2ax}

v_f = \sqrt{2.5*10^5+2*(1.49*10^{15})(0.1*10^{-2})}

v_f = 1.726*10^6 m/s

Therefore the electron's speed when it is 0.1 cm from the negative plate is 1.726*10^6 m/s

4 0
2 years ago
Rank the items from slowest to faster
valentinak56 [21]

Answer:since time goes to the right you look at the lines that are most pointed to the right with less distance so that would be B, A, D, C

Explanation:

5 0
2 years ago
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