<span> First you need to know how many isotopes there are of silicon, and its average atomic units (look at periodic table). Then make up a system of equations to solve for it. Theres 3 stable silicon isotopes (28, 29, 30) so you will need to have 3 equations. You must be given the percent abundance of at least one of the isotopes to solve because here I can only see 2 equations (numbered down below) set x = percent abundance of si-28 y = percent abundance of si-29 z = percent abundance of si-30 since all of silicon atoms account for 100% of all silicon: x + y + z = 100% = 1 therefore: 1) x = 1 - y - z You also have 2) 28x + 29y + 30z = average atomic mass you can substitute x so that equation becomes: 28 (1 - y - z) + 29y + 30z = average atomic mass See how you have 2 variables here? You cant go on until you know the value of one isotope already or you have given a clue which you can derive the third equation</span>
Precipitation occurs when the product of the ion concentration exceeds the Ksp.
Answer:
Rock A because after physical weather and chemical weathering it more likely for Rock A to experience more chemical weathering.
Explanation: Weathering: This is a geological term used to describe the various processes and Activities involved in the breaking down of rocks either through physical,mechanical,chemical etc actions into smaller particles.
ROCK A WILL HAVE MORE CHEMICAL WEATHERING BECAUSE THE PHYSICAL WEATHERING MUST HAVE BROKEN DOWN THE PARTICLES FOR EASY WATER AND OTHER SUBSTANCE NEEDED FOR EASIER CHEMICAL REACTION OR WEATHERING.
Burning charcoal is a chemical reaction called combustion
Answer:
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Explanation:
Step 1: Data given
Volume = 500 mL = 0.500 L
The concentration sodium sulfate = 2.104 M
Step 2: The equation
Na2SO4 → 2Na+ + SO4^2-
For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)
Step 3: Calculate the concentration of the ions
[Na+] = 2*2.104 M = 4.208 M
[SO4^2-] = 1*2.104 M = 2.104 M
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
